问题
i did some questions in here and them one guy gave me this code. But I need help because it is only bringing one result of my websites.txt
Crawler.py
import urllib.request
import re
regex = "<title>(.+?)</title>"
pattern = re.compile(regex)
txtfl = open('websites.txt')
webpgsinfile = txtfl.readlines()
urls = webpgsinfile
htmlfile = urllib.request.urlopen(urls[i])
htmltext = htmlfile.read().decode('utf8')
titles = re.findall(pattern,htmltext)
if len(titles) > 0:
print(titles[0])
i+=1
The websites.txt
http://youtube.com
http://bigsolutions.com.br
回答1:
import re
from urllib.request import urlopen
def get_page(url, encoding='utf-8'):
return urlopen(url).read().decode(encoding, errors='ignore')
def get_title(txt, reg=re.compile('<title>(.*)</title>', re.IGNORECASE | re.DOTALL)):
match = reg.search(txt)
if match is None:
return ''
else:
return match.group(1).strip()
def main():
with open('websites.txt') as inf:
urls = [line.strip() for line in inf]
titles = [get_title(get_page(url)) for url in urls if url]
print(titles)
if __name__=="__main__":
main()
results in
["LimeCD - Lime's Code Library", 'YouTube', 'Big Solutions - Aqui nós pensamos grande!']
回答2:
I'm still a python2 programmer, so forgive any errors because of that. Also note that this code is untested and it's just for you to get a feeling of what you need to do.
import urllib.request
import re
regex = "<title>(.+?)</title>"
pattern = re.compile(regex)
urls = open('websites.txt').readlines()
titles = []
for url in urls:
htmlfile = urllib.request.urlopen(url)
htmltext = htmlfile.read().decode('utf8')
titles.append(re.findall(pattern, htmltext))
print(titles)
What this does is it creates an array of the titles
you want, and then iterates through your urls and adds the title to the titles
array. I don't see how the original code compiled, but it looked like it was missing a loop.
来源:https://stackoverflow.com/questions/20308357/crawler-only-loads-one-title