问题
I'm trying to cancel my async
method call in Typescript.
To do this, I have created a new Promise type, which inherits from Promise
:
class CancelablePromise<T> extends Promise<T>{
public cancelMethod: () => void;
constructor(executor: (resolve: (value?: T | PromiseLike<T>) => void, reject: (reason?: any) => void) => void) {
super(executor);
// Set the prototype explicitly.
Object.setPrototypeOf(this, CancelablePromise.prototype);
}
//cancel the operation
public cancel() {
if (this.cancelMethod) {
this.cancelMethod();
}
}
}
The first version was without the Object.setPrototypeOf(..)
, but it was recommend on the TypeScript GitHub page
When I'm trying to use it, I get a run-time error (no compile errors):
class Test{
async postFileAjax<T>(file: File): CancelablePromise <T> {
var promiseFunc = (resolve) => { resolve() };
var promise = new CancelablePromise<T>(promiseFunc);
promise.cancelMethod = () => { console.log("cancel!") };
return promise;
}
}
var test = new Test();
test.postFileAjax(null);
Error:
(unknown) Uncaught TypeError: undefined is not a promise
at CancelablePromise.Promise (<anonymous>)
at new CancelablePromise (<anonymous>:44:28)
at __awaiter (<anonymous>:7:12)
at Test.postFileAjax (<anonymous>:62:16)
at <anonymous>:75:6
at HTMLButtonElement.excuteButton.onclick (https://www.typescriptlang.org/play/playground.js:242)
What am I doing wrong? I see that in ES6 you could subclass the Promise
(see stackoverflow question), so I would expect it also in TypeScript.
Using Typescript 2.1 and targeting es5
You can see the same result if you run the code in TypeScript Playground, click "run" and check the console (F12) in the new page.
How do I solve this runtime error?
PS: a related error on stackoverflow is here, but that a compile error and solved. I have split the compile and runtime error.
回答1:
I simplified your example; this runs without error:
interface CancelablePromise<T> extends Promise<T> {
cancel: () => void;
}
class Test {
postFileAjax<T>(file: File): CancelablePromise<T> {
const promiseFunc = (resolve) => { resolve() };
const promise = new Promise<T>(promiseFunc);
const cancel = () => { console.log("cancel!") };
const cancelablePromise = Object.assign(promise, { cancel });
return cancelablePromise;
}
}
const test = new Test();
const testPromise = test.postFileAjax(null);
testPromise.cancel();
TypeScript Playground
- I used interface inheritance rather than a new class.
- I copied the
cancel
function right ontopromise
.
来源:https://stackoverflow.com/questions/43420175/typescript-subclass-extend-of-promise-gives-typeerror-undefined-is-not-a-prom