问题
I want to compile my swift code written in the new Swift Package Manager format into highly optimized binary code. This is possible currently using swiftc -O somefile.swift But since the swift packages are built using swift build command, I cannot pass -O option as it does not accept it. So is there a way to specify to optimize the code during the compile process?
回答1:
You can build in a release configuration with: swift build --configuration release.
You can also see the tool usage via:
$ swift build --help
OVERVIEW: Build sources into binary products
USAGE: swift build [mode] [options]
MODES:
-c, --configuration <value> Build with configuration (debug|release) [default: debug]
--clean [<mode>] Delete artifacts (build|dist) [default: build]
OPTIONS:
-C, --chdir <path> Change working directory before any other operation
--build-path <path> Specify build/cache directory [default: ./.build]
--color <mode> Specify color mode (auto|always|never) [default: auto]
-v, --verbose Increase verbosity of informational output
-Xcc <flag> Pass flag through to all C compiler invocations
-Xlinker <flag> Pass flag through to all linker invocations
-Xswiftc <flag> Pass flag through to all Swift compiler invocations
NOTE: Use `swift package` to perform other functions on packages
which lists this option.
See the package manager reference for more information.
来源：https://stackoverflow.com/questions/39775937/how-to-build-optimized-version-of-swift-package-using-the-swift-package-manager