问题
I want to replace a certain string by another in a data frame here is a sample code:
table_ex <- data.frame(row.names = c("row 1", "row 2", "row 3"))
table_ex$year1 <- 3:1
table_ex$year2 <- c("NaN", 5, "NaN %")
table_ex$year3 <- c("NaN %", 7, "NaN %")
remove_symb <- function(yolo){stringr::str_replace(yolo, 'NaN %|NaN', '')}
table_ex <- mutate_all(table_ex, funs(remove_symb))
Doing the above is dropping my rownnames. I understand I could use a lapply function, but I'm wondering why are the row names dropped. Is it because of the str_replace
functions or the mutate_all
functions? And how should I prevent that?
回答1:
If we need to keep the row names, loop through the columns and assign it back to the original data and to keep the structure intact use []
.
table_ex[] <- lapply(table_ex, remove_symb)
table_ex
# year1 year2 year3
#row 1 3
#row 2 2 5 7
#row 3 1
Using dplyr
or data.table
will change the row names to numeric sequence, but with []
, we can still change it to the original row names
table_ex[] <- mutate_all(table_ex, funs(remove_symb))
来源:https://stackoverflow.com/questions/40968821/why-are-my-row-names-dropped-and-how-to-avoid-it