问题
I want to have a class that has a number of fields such as String, Boolean, etc and when the class is constructed I want to have a fieldname associated with each field and verify the field (using regex for strings). Ideally I would just like specify in the constructor that the parameter needs to meet certain criteria.
Some sample code of how :
case class Data(val name: String ..., val fileName: String ...) {
name.verify
// Access fieldName associated with the name parameter.
println(name.fieldName) // "Name"
println(fileName.fieldName) // "File Name"
}
val x = Data("testName", "testFile")
// Treat name as if it was just a string field in Data
x.name // Is of type string, does not expose fieldName, etc
Is there an elegant way to achieve this?
EDIT: I don't think I have been able to get across clearly what I am after. I have a class with a number of string parameters. Each of those parameters needs to validated in a specific way and I also want to have a string fieldName associated with each parameter. However, I want to still be able to treat the parameter as if it was just a normal string (see the example).
I could code the logic into Data and as an apply method of the Data companion object for each parameter, but I was hoping to have something more generic.
回答1:
Putting logic (such as parameter validation) in constructors is dubious. Throwing exceptions from constructors is doubly so.
Usually this kind of creational pattern is best served with one or more factory methods or a builder of some sort.
For a basic factory, just define a companion with the factory methods you want. If you want the same short-hand construction notation (new
-free) you can overload the predefined apply
(though you may not replace the one whose signature matches the case class
constructor exactly).
If you want to spare your client code the messiness of dealing with exceptions when validation fails, you can return Option[Data]
or Either[ErrorIndication, Data]
instead. Or you can go with ScalaZ's Validation
, which I'm going to arbitrarily declare to be beyond the scope of this answer ('cause I'm not sufficiently familiar with it...)
However, you cannot have instances that differ in what properties they present. Not even subclasses can subtract from the public API. If you need to be able to do that, you'll need a more elaborate construct such as a trait
for the common parts and separate case class
es for the variants and / or extensions.
来源:https://stackoverflow.com/questions/14865528/best-way-to-validate-and-extend-constructor-parameters-in-scala-2-10