Forward-declare a typedef

问题

I have got a large header file (~10000 lines) which is auto-generated by a script/program out of my control.

In order to avoid to include this file in the declaration of my class, I forward declare the few types I need:

--myclass.h

namespace bl {
   class TypeA;
   class TypeB;
}
// Other stuff and myclass definition...

Now it turns out that TypeA and TypeB are not class-names, but are instead defined inside the auto-generated file as:

typedef SomeUnspecifiedClassName TypeA;
typedef AnotherUnspecifiedClassName TypeB;

Where by SomeUnspecifiedClassName I mean that I can not forward-declare this type-name because it may change under various circumstances.

How can I forward-declare a typedef? (Can't use c++11)

回答1:

Simply - you can't. If you post your specific situations, though, there might be some workarounds to what you want to do.

回答2:

You can write a script that extracts the ...UnspecifedClassName from the typedef lines in your auto-generated source file. Then, this script would be the basis of your own auto-generated header file that would forward declare those classes, as well as your typedef statements to them. Your myclass.h file can then #include that header file.

回答3:

One relatively decent solution that I have found useful on occasion is to create a trivial wrapper class:

Place in a header file:

class ClassA;
// now use pointers and references to ClassA at will

Place in a source file:

#include <NastyThirdPartyHeader>

class ClassA: public TypeA {
public:
  ClassA(TypeA const &x): TypeA(x) {}
  ClassA &operator=(TypeA const &x) {
    TypeA::operator=(x);
    return *this;
  }
};

Depending on your use case, that may be all you need.

来源：https://stackoverflow.com/questions/16287578/forward-declare-a-typedef