问题
If I have a basic bitmask...
cat = 0x1;
dog = 0x2;
chicken = 0x4;
cow = 0x8;
// OMD has a chicken and a cow
onTheFarm = 0x12;
...how can I check if only one animal (i.e. one bit) is set?
The value of onTheFarm
must be 2n, but how can I check that programmatically (preferably in Javascript)?
回答1:
You can count the number of bits that are set in a non-negative integer value with this code (adapted to JavaScript from this answer):
function countSetBits(i)
{
i = i - ((i >> 1) & 0x55555555);
i = (i & 0x33333333) + ((i >> 2) & 0x33333333);
return (((i + (i >> 4)) & 0x0F0F0F0F) * 0x01010101) >> 24;
}
It should be much more efficient than examining each bit individually. However, it doesn't work if the sign bit is set in i
.
EDIT (all credit to Pointy's comment):
function isPowerOfTwo(i) {
return i > 0 && (i & (i-1)) === 0;
}
回答2:
You have to check bit by bit, with a function more or less like this:
function p2(n) {
if (n === 0) return false;
while (n) {
if (n & 1 && n !== 1) return false;
n >>= 1;
}
return true;
}
Some CPU instruction sets have included a "count set bits" operation (the ancient CDC Cyber series was one). It's useful for some data structures implemented as bit collections. If you've got a set implemented as a string of integers, with bit positions corresponding to elements of the set data type, then getting the cardinality involves counting bits.
edit wow looking into Ted Hopp's answer I stumbled across this:
function p2(n) {
return n !== 0 && (n & (n - 1)) === 0;
}
That's from this awesome collection of "tricks". Things like this problem are good reasons to study number theory :-)
回答3:
If you're looking to see if only a single bit is set, you could take advantage of logarithms, as follows:
var singleAnimal = (Math.log(onTheFarm) / Math.log(2)) % 1 == 0;
Math.log(y) / Math.log(2)
finds the x
in 2^x = y
and the x % 1
tells us if x
is a whole number. x
will only be a whole number if a single bit is set, and thus, only one animal is selected.
来源:https://stackoverflow.com/questions/15951776/bitmask-how-to-determine-if-only-one-bit-is-set