Use a local variable in preg_replace_callback - PHP

问题

How to use a local variable in preg_replace_callback in PHP. I have the following code:

function pregRep($matches)
{
    global $i; $i++;

    if($i > 2)
    {     
          return '#'.$matches[0];
    }
    else
    {
        return $matches[0];
    }
}

$i = 0;
$str =  preg_replace_callback($reg_exp,"pregRep",$str); 

And also $str is a string, $reg_exp is a regex expression. Both of these are well defined.

Thanks for your help.

回答1:

The easiest way is with an anonymous callback:

$str = preg_replace_callback($regExp,function($match) use ($some_local_variable) {
    // do something
},$str);

Note that you can add multiple variables in this way, but it will create a copy of that variable as it is when the function is defined (this is important if you are assigning it to a variable for multiple uses). If you want a "live" reference to the variable, use &$some_var.

Of course, this requires PHP 5.3 or newer.

来源：https://stackoverflow.com/questions/15934249/use-a-local-variable-in-preg-replace-callback-php