How to build a sparse matrix in PySpark?

问题

I am new to Spark. I would like to make a sparse matrix a user-id item-id matrix specifically for a recommendation engine. I know how I would do this in python. How does one do this in PySpark? Here is how I would have done it in matrix. The table looks like this now.

Session ID| Item ID | Rating
     1          2       1
     1          3       5

    import numpy as np

    data=df[['session_id','item_id','rating']].values
    data

    rows, row_pos = np.unique(data[:, 0], return_inverse=True)
    cols, col_pos = np.unique(data[:, 1], return_inverse=True)

    pivot_table = np.zeros((len(rows), len(cols)), dtype=data.dtype)
    pivot_table[row_pos, col_pos] = data[:, 2]

回答1:

Like that:

from pyspark.mllib.linalg.distributed import CoordinateMatrix, MatrixEntry

# Create an RDD of (row, col, value) triples
coordinates = sc.parallelize([(1, 2, 1), (1, 3, 5)])
matrix = CoordinateMatrix(coordinates.map(lambda coords: MatrixEntry(*coords)))

来源：https://stackoverflow.com/questions/38134370/how-to-build-a-sparse-matrix-in-pyspark