Calculating 2^N in C# with long data type where N is 1929439432949324 [closed]

问题

Currently I need to calculate 2^N, however N can be as large as 1929238932899 and I'm stuck using a long data type which can't hold a number that large.

I've currently tried converting to 'BigInt' however I'm still stuck with the long data type restriction from what I've seen as well.

I have a function which calculates the power. However, with the long data type, it just returns 0 when the number gets too big. Note that this is just a generic recursive power function.

For example, with 2^6 its meant to return 64 and with 2^47 to return 140737488355328. However, when it becomes 2^8489289, it just returns 0.

回答1:

To represent 2^N in binary form, you need N+1 bits (binary digits), that is

(1 929 439 432 949 324 + 1) / 8 = 241 179 929 118 665.6 bytes ~ 219 PiB for a single number, if you really want to work with it.

Or you can just write down 2^N in binary form: 1 followed by N zeroes.

回答2:

Since 2^N is an integer, you can represented it using Integer factorization.

You can put that in a class like this:

class FactorizedInteger {

    private Dictionary<long, long> _factors = new Dictionary<long, long>();

    public FactorizedInteger(long radix, long exponent) {
        _factors[radix] = exponent;
    }

    public void Add(FactorizedInteger other) {
        foreach(var factor in other._factors) {
            if (_factors.ContainsKey(factor.Key)) {
                _factors[factor.Key] += factor.Value;
            } else {
                _factors[factor.Key] = factor.Value;
            }
        }
    }

    public override string ToString() {
        return "(" + String.Join(" + ", _factors.Select(p => $"{p.Key}^{p.Value}")) + ")";
    }
}

As you can see, you can even add some mathematical operations without exhausting the memory of the computer. I've included Add as an example.

To use it:

        var e1 = new FactorizedInteger(2, 1929238932899);
        var e2 = new FactorizedInteger(2, 64);
        Console.WriteLine(e1);

        e1.Add(e2);
        Console.WriteLine(e1);

Output:

(2^1929238932899)
(2^1929238932963)

This example needs to be made much smarter to be really usefull, but it is a possible representation of such large numbers.

来源：https://stackoverflow.com/questions/57721004/calculating-2n-in-c-sharp-with-long-data-type-where-n-is-1929439432949324

标签

numbers

exponential