问题
I am working on HCUP data and this has range of values in one single column that needs to be split into multiple columns. Below is the HCUP data frame for reference :
code label
61000-61003 excision of CNS
0169T-0169T ventricular shunt
The desired output should be :
code label
61000 excision of CNS
61001 excision of CNS
61002 excision of CNS
61003 excision of CNS
0169T ventricular shunt
My approach to this problem is using the package splitstackshape and using this code
library(data.table)
library(splitstackshape)
cSplit(hcup, "code", "-")[, list(code = code_1:code_2, by = label)]
This approach leads to memory issues. Is there a better approach to this problem?
Some comments :
- The data has many letters apart from "T".
- The letter can be either in the front or at the very end but not in between two numbers.
- There is no change of letter from "T" to "U" in one single range
回答1:
Here's a solution using dplyr and all.is.numeric from Hmisc:
library(dplyr)
library(Hmisc)
library(tidyr)
dat %>% separate(code, into=c("code1", "code2")) %>%
rowwise %>%
mutate(lists = ifelse(all.is.numeric(c(code1, code2)),
list(as.character(seq(from = as.numeric(code1), to = as.numeric(code2)))),
list(code1))) %>%
unnest(lists) %>%
select(code = lists, label)
Source: local data frame [5 x 2]
code label
(chr) (fctr)
1 61000 excision of CNS
2 61001 excision of CNS
3 61002 excision of CNS
4 61003 excision of CNS
5 0169T ventricular shunt
An edit to fix ranges with character values. Brings down the simplicity a little:
dff %>% mutate(row = row_number()) %>%
separate(code, into=c("code1", "code2")) %>%
group_by(row) %>%
summarise(lists = if(all.is.numeric(c(code1, code2)))
{list(str_pad(as.character(
seq(from = as.numeric(code1), to = as.numeric(code2))),
nchar(code1), pad="0"))}
else if(grepl("^[0-9]", code1))
{list(str_pad(paste0(as.character(
seq(from = extract_numeric(code1), to = extract_numeric(code2))),
strsplit(code1, "[0-9]+")[[1]][2]),
nchar(code1), pad = "0"))}
else
{list(paste0(
strsplit(code1, "[0-9]+")[[1]],
str_pad(as.character(
seq(from = extract_numeric(code1), to = extract_numeric(code2))),
nchar(gsub("[^0-9]", "", code1)), pad="0")))},
label = first(label)) %>%
unnest(lists) %>%
select(-row)
Source: local data frame [15 x 2]
label lists
(chr) (chr)
1 excision of CNS 61000
2 excision of CNS 61001
3 excision of CNS 61002
4 ventricular shunt 0169T
5 ventricular shunt 0170T
6 ventricular shunt 0171T
7 excision of CNS 01000
8 excision of CNS 01001
9 excision of CNS 01002
10 some procedure A2543
11 some procedure A2544
12 some procedure A2545
13 some procedure A0543
14 some procedure A0544
15 some procedure A0545
data:
dff <- structure(list(code = c("61000-61002", "0169T-0171T", "01000-01002",
"A2543-A2545", "A0543-A0545"), label = c("excision of CNS", "ventricular shunt",
"excision of CNS", "some procedure", "some procedure")), .Names = c("code",
"label"), row.names = c(NA, 5L), class = "data.frame")
回答2:
Original Answer: See below for update.
First, I made your example data a little more challenging by adding the first row to the bottom.
dff <- structure(list(code = c("61000-61003", "0169T-0169T", "61000-61003"
), label = c("excision of CNS", "ventricular shunt", "excision of CNS"
)), .Names = c("code", "label"), row.names = c(NA, 3L), class = "data.frame")
dff
# code label
# 1 61000-61003 excision of CNS
# 2 0169T-0169T ventricular shunt
# 3 61000-61003 excision of CNS
We can use the sequence operator : to get the sequences for the code column, wrapping with tryCatch() so we can avoid an error on, and save the values that cannot be sequenced. First we split the values by the dash mark - then run it through lapply().
xx <- lapply(
strsplit(dff$code, "-", fixed = TRUE),
function(x) tryCatch(x[1]:x[2], warning = function(w) x)
)
data.frame(code = unlist(xx), label = rep(dff$label, lengths(xx)))
# code label
# 1 61000 excision of CNS
# 2 61001 excision of CNS
# 3 61002 excision of CNS
# 4 61003 excision of CNS
# 5 0169T ventricular shunt
# 6 0169T ventricular shunt
# 7 61000 excision of CNS
# 8 61001 excision of CNS
# 9 61002 excision of CNS
# 10 61003 excision of CNS
We're trying to apply the sequence operator : to each element from strsplit(), and if taking x[1]:x[2] is not possible then this returns just the values for those elements and proceeds with the sequence x[1]:x[2] otherwise. Then we just replicate the values of the label column based on the resulting lengths in xx to get the new label column.
Update: Here is what I've come up with in response to your edit. Replace xx above with
xx <- lapply(strsplit(dff$code, "-", TRUE), function(x) {
s <- stringi::stri_locate_first_regex(x, "[A-Z]")
nc <- nchar(x)[1L]
fmt <- function(n) paste0("%0", n, "d")
if(!all(is.na(s))) {
ss <- s[1,1]
fmt <- fmt(nc-1)
if(ss == 1L) {
xx <- substr(x, 2, nc)
paste0(substr(x, 1, 1), sprintf(fmt, xx[1]:xx[2]))
} else {
xx <- substr(x, 1, ss-1)
paste0(sprintf(fmt, xx[1]:xx[2]), substr(x, nc, nc))
}
} else {
sprintf(fmt(nc), x[1]:x[2])
}
})
Yep, it's complicated. Now if we take the following data frame df2 as a test case
df2 <- structure(list(code = c("61000-61003", "0169T-0174T", "61000-61003",
"T0169-T0174"), label = c("excision of CNS", "ventricular shunt",
"excision of CNS", "ventricular shunt")), .Names = c("code",
"label"), row.names = c(NA, 4L), class = "data.frame")
and run the xx code from above on it, we can get the following result.
data.frame(code = unlist(xx), label = rep(df2$label, lengths(xx)))
# code label
# 1 61000 excision of CNS
# 2 61001 excision of CNS
# 3 61002 excision of CNS
# 4 61003 excision of CNS
# 5 0169T ventricular shunt
# 6 0170T ventricular shunt
# 7 0171T ventricular shunt
# 8 0172T ventricular shunt
# 9 0173T ventricular shunt
# 10 0174T ventricular shunt
# 11 61000 excision of CNS
# 12 61001 excision of CNS
# 13 61002 excision of CNS
# 14 61003 excision of CNS
# 15 T0169 ventricular shunt
# 16 T0170 ventricular shunt
# 17 T0171 ventricular shunt
# 18 T0172 ventricular shunt
# 19 T0173 ventricular shunt
# 20 T0174 ventricular shunt
回答3:
Create a sequencing rule for such codes:
seq_code <- function(from,to){
ext = function(x, part) gsub("([^0-9]?)([0-9]*)([^0-9]?)", paste0("\\",part), x)
pre = unique(sapply(list(from,to), ext, part = 1 ))
suf = unique(sapply(list(from,to), ext, part = 3 ))
if (length(pre) > 1 | length(suf) > 1){
return("NO!")
}
num = do.call(seq, lapply(list(from,to), function(x) as.integer(ext(x, part = 2))))
len = nchar(from)-nchar(pre)-nchar(suf)
paste0(pre, sprintf(paste0("%0",len,"d"), num), suf)
}
With @jeremycg's example:
setDT(dff)[,.(
label = label[1],
code = do.call(seq_code, tstrsplit(code,'-'))
), by=.(row=seq(nrow(dff)))]
which gives
row label code
1: 1 excision of CNS 61000
2: 1 excision of CNS 61001
3: 1 excision of CNS 61002
4: 2 ventricular shunt 0169T
5: 2 ventricular shunt 0170T
6: 2 ventricular shunt 0171T
7: 3 excision of CNS 01000
8: 3 excision of CNS 01001
9: 3 excision of CNS 01002
10: 4 some procedure A2543
11: 4 some procedure A2544
12: 4 some procedure A2545
13: 5 some procedure A0543
14: 5 some procedure A0544
15: 5 some procedure A0545
Data copied from @jeremycg's answer:
dff <- structure(list(code = c("61000-61002", "0169T-0171T", "01000-01002",
"A2543-A2545", "A0543-A0545"), label = c("excision of CNS", "ventricular shunt",
"excision of CNS", "some procedure", "some procedure")), .Names = c("code",
"label"), row.names = c(NA, 5L), class = "data.frame")
回答4:
If you're patient enough, you'd probably parse the strings into separate pieces instead of the eval/parse trick, alas I'm not, so:
fancy.seq = function(x) eval(parse(text=sub(', \\)', ')', sub('\\(, ', '(',
sub('.*?([0-9]+)(.*)-(.*?)([1-9][0-9]*).*',
'paste0("\\3",
formatC(\\1:\\4, width=log10(\\4)+1, format="d", flag="0"),
"\\2")',
x)))))
# using example from jeremycg's answer
dt[, .(fancy.seq(code), label), by = 1:nrow(dt)]
# nrow V1 label
# 1: 1 61000 excision of CNS
# 2: 1 61001 excision of CNS
# 3: 1 61002 excision of CNS
# 4: 2 0169T ventricular shunt
# 5: 2 0170T ventricular shunt
# 6: 2 0171T ventricular shunt
# 7: 3 01000 excision of CNS
# 8: 3 01001 excision of CNS
# 9: 3 01002 excision of CNS
#10: 4 A2543 some procedure
#11: 4 A2544 some procedure
#12: 4 A2545 some procedure
#13: 5 A0543 some procedure
#14: 5 A0544 some procedure
#15: 5 A0545 some procedure
If unclear what the above is doing - just run the sub commands one by one on one of the "code" strings.
回答5:
A less elegant way to do it:
# the data
hcup <- data.frame(code=c("61000-61003", "0169T-0169T"),
label=c("excision of CNS", "ventricular shunt"), stringsAsFactors = F)
hcup
> code label
>1 61000-61003 excision of CNS
>2 0169T-0169T ventricular shunt
# reshaping
# split the code ranges into separate columns
seq.ends <- cbind(do.call(rbind.data.frame, strsplit(hcup$code, "-")), hcup$label)
# create a list with a data.frame for each original line
new.list <- apply(seq.ends, 1, FUN=function(x){data.frame(code=if(grepl("\\d{5}", x[1])){
z<-x[1]:x[2]}else{z<-x[1]}, label=rep(x[3], length(z)),
stringsAsFactors = F)})
# collapse the list into a df
new.df <- do.call(rbind, lapply(new.list, data.frame, stringsAsFactors=F))
new.df
> code label
>1.1 61000 excision of CNS
>1.2 61001 excision of CNS
>1.3 61002 excision of CNS
>1.4 61003 excision of CNS
>2 0169T ventricular shunt
来源：https://stackoverflow.com/questions/33113263/splitting-a-single-column-into-multiple-observation-using-r