问题
I'm writing some code that basically follows the following format:
public static boolean isIncluded(E element) {
Node<E> c = head;
while (c != null) {
if (cursor.getElement().equals(element)) {
return true;
}
c = c.getNext();
}
return false;
}
The code will search for an element in a list of nodes. However, my question is that if the while loop does find the element where the if-statement says it should return true, will it simply return true and break the loop? Furthermore, if it does then break the loop will it then carry on through the method and still return false, or is the method completed once a value is returned?
Thanks
回答1:
Yes*
Yes, usually (and in your case) it does break out of the loop and returns from the method.
An Exception
One exception is that if there is a finally block inside the loop and surrounding the return statement then the code in the finally block will be executed before the method returns. The finally block might not terminate - for example it could contain another loop or call a method that never returns. In this case you wouldn't ever exit the loop or the method.
while (true)
{
try
{
return; // This return technically speaking doesn't exit the loop.
}
finally
{
while (true) {} // Instead it gets stuck here.
}
}
回答2:
Return does break the loop and returns from the entire method immediately. The only code that will be executed on the way out is the body of a finally
clause and the release of any synchronized
statement.
回答3:
I should also add that if you want to break the current iteration of the loop, and instantly start the next one, you can use:
continue;
As it seems nobody has suggested it.
回答4:
Yes.
Anyway, for questions as short as this, I think you would be better (and get an earlier answer) just trying it by yourself.
回答5:
Return whenever called exits a method from wherever it is and returns a value to the caller.
来源:https://stackoverflow.com/questions/10661081/java-does-returning-a-value-break-a-loop