How to display Contacts in alphabetic order in Listview [closed]

久未见 提交于 2019-12-03 03:17:30
N.Zyzek

You need to do this:

Cursor cursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC");

use this code to retrieve the contacts

ArrayList<HashMap<String,String>> contactData=new ArrayList<HashMap<String,String>>();
ContentResolver cr = getContentResolver();
     Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null);
     while (cursor.moveToNext()) {
         try{
         String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID)); 
         String name=cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
         String hasPhone = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)); 
         if (Integer.parseInt(cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
             Cursor phones = getContentResolver().query( ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ contactId, null, null);
             while (phones.moveToNext()) { 
                 String phoneNumber = phones.getString(phones.getColumnIndex( ContactsContract.CommonDataKinds.Phone.NUMBER));
                 HashMap<String,String> map=new HashMap<String,String>();
                 map.put("name", name);
                 map.put("number", phoneNumber);
                 contactData.add(map);
             } 
             phones.close(); 
         }
     }catch(Exception e){}
     }

Now the contact details are stored in the contactData ArrayList. Now sort this arrayList like bellow

Collections.sort(contactData, new Comparator(){
                @Override
                public int compare(Object o1, Object o2) {
                    HashMap map1=(HashMap)o1;
                    HashMap map2=(HashMap)o2;
                    String s1=(String)map1.get("name");
                    String s2=(String)map2.get("name");
                    return s1.compareTo(s2);
                }
            });

Now the contact details are stored in the sorting order in the contactData ArrayList.

I have added Alphabetic headers to contact list

new ReadContactTask(context, showProgressDialog,new OnContactReadListener() {
            @Override
            public void onContactRead(List<ContactItem> dummyList) {

                ArrayList<ContactItem> latestPhoneContacts = new ArrayList<>();

                if(dummyList!=null && dummyList.size()>0)
                {
                    tvNoResult.setVisibility(View.GONE);

                    for(ContactItem contactItem : dummyList){
                        String contactNameInCapital = "";
                        if(contactItem.getContactName()!=null && contactItem.getContactName().length()>2){
                            contactNameInCapital = contactItem.getContactName().substring(0,1).toUpperCase();

                            if(contactNameInCapital.charAt(0) != previousContact.charAt(0))
                            {
                                latestPhoneContacts.add(new ContactItem(contactNameInCapital.substring(0,1)));
                                latestPhoneContacts.add(contactItem);
                            }
                            else
                            {
                                latestPhoneContacts.add(contactItem);
                            }

                            previousContact = contactNameInCapital;
                        }
                    }
                    if(latestPhoneContacts!=null && latestPhoneContacts.size()>0)
                        contactListAdapter.addItems(latestPhoneContacts);
                }
            }

            @Override
            public void onContactEmpty() {

            }
        }).execute();

where

private String previousContact ="Zee";
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