ziparchive

I'm using PHPExcel to export some data to user in an excel file. I would like the script to send the excel file to the user immediately after it's creation. Here is my test code: try{ /* Some test data */ $data = array( array(1, 10 , 2 ,), array(3, 'qqq', 'some string' ,), ); $objPHPExcel = new PHPExcel(); $objPHPExcel->setActiveSheetIndex(0); /* Fill the excel sheet with the data */ $rowI = 0; foreach($data as $row){ $colI = 0; foreach($row as $v){ $colChar = PHPExcel_Cell::stringFromColumnIndex($colI++); $cellId = $colChar.($rowI+1); $objPHPExcel->getActiveSheet()->SetCellValue($cellId, $v);

Well, first of all, this is my folder structure: images/ image1.png image11.png image111.png image223.png generate_zip.php And this is mine generate_zip.php: <?php $files = array($listfiles); $zipname = 'adcs.zip'; $zip = new ZipArchive; $zip->open($zipname, ZipArchive::CREATE); foreach ($files as $file) { $zip->addFile($file); } $zip->close(); header('Content-Type: application/zip'); header("Content-Disposition: attachment; filename='adcs.zip'"); header('Content-Length: ' . filesize($zipname)); header("Location: adcs.zip"); ?> How to gather all the files from "images/" folder, except

I have a problem that I install 'Archive_Zip 0.1.1' on Linux server, but when I try to run the script to create the zip file it gives the fatal error Fatal error: Class ZipArchive not found in ... where I put the code $zip = new ZipArchive; var_dump($zip); $res = $zip->open($filename, ZipArchive::OVERWRITE); if ($res !== TRUE) { echo 'Error: Unable to create zip file'; exit; } if (is_file($src)) { $zip->addFile($src); } else { // echo "<br>" . dirname(__FILE__) . $src;//'/install1'; if (!is_dir($src)) { $zip->close(); @unlink($filename); echo 'Error: File not found'; exit; } recurse_zip($src,

I have archive.zip with two files: hello.txt and world.txt I want to overwrite hello.txt file with new one with that code: import zipfile z = zipfile.ZipFile('archive.zip','a') z.write('hello.txt') z.close() but it won't overwrite file, somehow it creates another instance of hello.txt — take a look at winzip screenshot: Since there is no smth like zipfile.remove() , what's the best way to handle this problem? There's no way to do that with python zipfile module. You have to create a new zip file and recompress everything again from the first file, plus the new modified file. Below is some code

I'm trying to create a ZIP archive with a simple demo text file using a MemoryStream as follows: using (var memoryStream = new MemoryStream()) using (var archive = new ZipArchive(memoryStream , ZipArchiveMode.Create)) { var demoFile = archive.CreateEntry("foo.txt"); using (var entryStream = demoFile.Open()) using (var streamWriter = new StreamWriter(entryStream)) { streamWriter.Write("Bar!"); } using (var fileStream = new FileStream(@"C:\Temp\test.zip", FileMode.Create)) { stream.CopyTo(fileStream); } } If I run this code, the archive file itself is created but foo.txt isn't. However, if I