ushort

问题 After reading all of the questions and answers on bit shifting/masking, I simply cannot wrap my head around it. I'm just not understanding how it works on a fundamental level. I've been able to achieve various techniques by using BitArray and BitConverter instead, but I really would like to understand bit shifting/masking better. The specific need I have is to do the following: I have a ushort: 0x810E (33038) Using bit shifting/masking, I'd like to know how to: Get the 16th bit Result: 1 Get

问题 How do I split a ushort into two byte variables in C#? I tried the following (package.FrameID is ushort): When I try to calculate this with paper&pencil I get the right result. Also, if FrameID is larger than a byte (so the second byte isn't zero), it works. array[0] = (byte)(0x0000000011111111 & package.FrameID); array[1] = (byte)(package.FrameID >> 8); In my case package.FrameID is 56 and the result in array[0] is 16 instead of 56. How can I fix this? 回答1: 0x0000000011111111 is not a binary

问题 I have a problem with converting raw-bytes values into java types. I am receiving bytes by a datagram socket as a bytes array. I know exactly which bytes means what, but I don't know how to convert them appropriately (I mean I know offsets, but don't know if what I think I received is correct ;)). For example, I want to convert 16 bit unsigned short into java int type. I found some examples in the web, the one is: public int getUShort(byte[] bytes, int offset) { int b0 = bytes[offset] & oxFF;