urllib

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm debugging a simple program, that has worked in the past. I've singled out the instruction where the error takes place, but I cannot figure out what triggers it. I've read all questions related to WinError 10061, but I do not see a clear answer urllib.request.urlopen('http://www.wikipedia.org/') Traceback (most recent call last): File "C:\Python33\lib\urllib\request.py", line 1248, in do_open h.request(req.get_method(), req.selector, req.data, headers) File "C:\Python33\lib\http\client.py", line 1061, in request self._send_request(method,

运行平台：Windows Python版本：Python3.x IDE：Sublime text3 转载请注明作者和出处： http://blog.csdn.net/c406495762/article/details/58716886 一直想学习Python爬虫的知识，在网上搜索了一下，大部分都是基于Python2.x的。因此打算写一个Python3.x的爬虫笔记，以便后续回顾，欢迎一起交流、共同进步。 1.Python3.x基础知识学习： 可以在通过如下方式进行学习： (1)廖雪峰Python3教程(文档)： URL： http://www.liaoxuefeng.com/ (2)菜鸟教程Python3教程(文档)： URL： http://www.runoob.com/python3/python3-tutorial.html (3)鱼C工作室Python教程(视频)： 小甲鱼老师很厉害，讲课风格幽默诙谐，如果时间充裕可以考虑看视频。 URL： http://www.fishc.com/ 2.开发环境搭建： Sublime text3搭建Pyhthon IDE可以查看博客: URL： http://www.cnblogs.com/nx520zj/p/5787393.html URL： http://blog.csdn.net/c406495762/article

Python版本：3.6 urllib官方文档 urllib由几个和url相关的模块组成： urllib.request for opening and reading URLs urllib.error containing the exceptions raised by urllib.request urllib.parse for parsing URLs urllib.robotparser for parsing robots.txt files urlopen urllib.request.urlopen(url, data=None, [timeout, ]*, cafile=None, capath=None, cadefault=False, context=None) import urllib # 使用urlopen进行get请求 response = urllib.request.urlopen( 'http://www.baidu.com' ) print(response.read().decode( 'utf-8' )) # 带请求参数的get请求 import urllib.parse data = bytes(urllib.parse.urlencode({ 'word' : 'hello' }), encoding= 'utf8' )

Urllib 官方文档地址： https://docs.python.org/3/library/urllib.html 其主要包括一下模块： urllib.request 请求模块 urllib.error 异常处理模块 urllib.parse url解析模块 urllib.robotparser robots.txt解析模块 　　 　　urllib.request.urlopen 　　 　　　urlopen参数如下： 　　 urllib . request . urlopen ( url , data = None , [ timeout , ]*, cafile = None , capath = None , cadefault = False , context = None 常用参数： 　　url:访问的地址，一般不只是地址。 　　data:此参数为可选字段，特别要注意的是，如果选择，请求变为post传递方式,其中传递的参数需要转为bytes，如果是我们只需要通过 urllib.parse.urlencode 转换即可： import urllib . parse import urllib . request data = bytes ( urllib . parse . urlencode ({ "word" : "python" }), encoding =

2019独角兽企业重金招聘Python工程师标准>>> GET方式示例【百度搜索】 #encoding:UTF-8 import urllib import urllib.request #数据字典 data={} data['word']='python3' #注意Python2.x的区别 url_values=urllib.parse.urlencode(data) print(url_values) url="http://www.baidu.com/s?" full_url=url+url_values data=urllib.request.urlopen(full_url).read() z_data=data.decode('UTF-8') print(z_data) 转载于:https://my.oschina.net/tanweijie/blog/195285 文章来源: https://blog.csdn.net/weixin_34061042/article/details/92072572

一.urllib库 　　urllib是Python自带的一个用于爬虫的库，其主要作用就是可以通过代码模拟浏览器发送请求。其常被用到的子模块在Python3中的为urllib.request和urllib.parse，在Python2中是urllib和urllib2。 二.由易到难的爬虫程序： 　　1.爬取百度首页面所有数据值 1 #!/usr/bin/env python 2 # -*- coding:utf-8 -*- 3 #导包 4 import urllib.request 5 import urllib.parse 6 if __name__ == "__main__": 7 #指定爬取的网页url 8 url = 'http://www.baidu.com/' 9 #通过urlopen函数向指定的url发起请求，返回响应对象 10 reponse = urllib.request.urlopen(url=url) 11 #通过调用响应对象中的read函数，返回响应回客户端的数据值（爬取到的数据） 12 data = reponse.read()#返回的数据为byte类型，并非字符串 13 print(data)#打印显示爬取到的数据值。 #补充说明 urlopen函数原型：urllib.request.urlopen(url, data=None, timeout=

As part of my quest to become better at Python I am now attempting to sign in to a website I frequent, send myself a private message, and then sign out. So far, I've managed to sign in (using urllib, cookiejar and urllib2). However, I cannot work out how to fill in the required form to send myself a message. The form is located at /messages.php?action=send. There's three things that need to be filled for the message to send: three text fields named name, title and message. Additionally, there is a submit button (named "submit"). How can I fill in this form and send it? import urllib import

I just rented a VPS from Linode which has python2.5 and ubuntu 8.04. When I run this command from python shell: import urllib I get: ImportError: No module named urllib What can be the reason? How can I add this module to python? Isn't it prepackaged with the basic version? Can it be PYTHONPATH problem? Ok, I resolved the issue. Somehow, python-tk package (which includes urllib) was missing. So the following line fixed the problem apt-get install python-tk I use a later OS, so I don't know if this will help, but just in case: marcelo@localhost:~$ lsb_release -a No LSB modules are available.

I am trying to access a specific site using python, and no matter which lib I use I just can't seem to access it. I have tried Selenium+PhantomJS, I have tried requests and urllib. Whenever I try to access the site from the browser I get a json file, and whenever I try to access it from a python script I get an html file (which has a huge minified script inside it) I suspect this site is detecting I'm sending the request headlessly and is blocking my requests, but I can't figure out how. The site address is: http://www.yesplanet.co.il/presentationsJSON I would very much appreciate if anyone