unzip

Unzip files in swift

由 血红的双手。 提交于 2019-12-29 05:30:07
问题 How to go about unzipping a file in swift? In Objective-C, I used SSZipArchive and I loved it. As seen in the code below. I suspect if I decide to keep SSZipArchive, I will have to bridge an Objective-C file to my Swift file. Is there any updated third-party, or better yet Apple-Documentation to unzip a file in Swift? NSString *zipPath = [self.globalFileStrucure stringByAppendingPathComponent:@"zipfile.zip"]; [data writeToFile:zipPath options:0 error:&error]; BOOL unZipped = 0; unZipped =

Read a zip file inside zip file

由 拈花ヽ惹草 提交于 2019-12-29 01:34:16
问题 I have zip file which is inside a folder in zip file please suggest me how to read it using zip input stream. E.G.: abc.zip | documents/bcd.zip How to read a zip file inside zip file? 回答1: If you want to look through zip files within zip files recursively, public void lookupSomethingInZip(InputStream fileInputStream) throws IOException { ZipInputStream zipInputStream = new ZipInputStream(fileInputStream); String entryName = ""; ZipEntry entry = zipInputStream.getNextEntry(); while (entry!

Linux 下压缩与解压.zip 和 .rar

由 喜欢而已 提交于 2019-12-28 21:11:19
1)对于.zip linux下提供了zip和unzip程序，zip是压缩程序，unzip是解压程序。它们的参数选项很多，可用命令zip -help和unzip -help查看，这里只做简单介绍，举例说明一下其用法： # zip test.zip test.jpg test.png 这条命令是将test.jpg和test.png压缩成一个zip包 # zip test.zip *.jpg 这条命令是将所有.jpg的文件压缩成一个zip包 # zip -r test.zip test 这条命令是将文件夹test压缩成一个zip包 # unzip test.zip 这条命令是将test.zip中的所有文件解压出来 　把/home目录下面的mydata目录压缩为mydata.zip 　# zip -r mydata.zip mydata #压缩mydata目录 　把/home目录下面的mydata.zip解压到mydatabak目录里面 　# unzip mydata.zip -d mydatabak 2)对于.rar 安装： sudo apt-get install rar unrar 或者可从http://www.rarsoft.com/download.htm下载 RAR for Linux 编译安装 # tar -xzpvf rarlinux-3.8.0.tar.gz # cd

How to get Inno Setup to unzip a file it installed (all as part of the one installation process)

由 六眼飞鱼酱① 提交于 2019-12-28 02:05:12
问题 To save bandwidth/space as well as prevent accidental meddling, the installation files for a database product (call it Ajax), have been zipped up (call that file "AJAX_Install_Files.ZIP). I would like to have Inno-Setup "install" (i.e., copy) the AJAX_Install_Files.ZIP file to the destination, and then Unzip the files into the same folder where the .ZIP file is located. A subsequent program would be fired off by Inno Setup to actually run the install of product "Ajax". I've looked through the

unzip file in C# via Winzip and its cmd extension

由 两盒软妹~` 提交于 2019-12-25 18:36:34
问题 so I have a small chunk of code that detects files in a folder and systematically zips them after they become a certain age. I'm now working on a piece of code to unzip files of a certain date-range at user request for use in the software. My issue is that the command-line string to zip files works great, but the unzip does not... below is the excerpt of code showing how I unzip, please let me know what I should do differently to ensure unzipping. thanks! private void UnZipFile() { if

Unzip file from server http

由 ￣綄美尐妖づ 提交于 2019-12-25 17:08:29
问题 I have a problem to unzip a file received from server. I send a request, and server show me a text with code characters :S With this code i receive a zip from server, but i need this text file unziped, and show in a EdText. public void postLoginData() { // Create a new HttpClient and Post Header HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost( "http://localhost:80/MOBILE/MBSERVER.V25?"); try { String VENDED_VEN = "2", EMPRES_CFG = "1", VERSAO_CFG = "100",

Unzip file from server http

由 那年仲夏 提交于 2019-12-25 17:08:04
问题 I have a problem to unzip a file received from server. I send a request, and server show me a text with code characters :S With this code i receive a zip from server, but i need this text file unziped, and show in a EdText. public void postLoginData() { // Create a new HttpClient and Post Header HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost( "http://localhost:80/MOBILE/MBSERVER.V25?"); try { String VENDED_VEN = "2", EMPRES_CFG = "1", VERSAO_CFG = "100",

Waiting for unzip to finish before carrying on C++ code on a RedHat machine

由 梦想的初衷 提交于 2019-12-25 08:38:25
问题 I want to unzip a zipped folder on my Redhat machine. To do this I send a bash script the string; "unzip /usr/bin/Folder.gz" This unzips the folder no problem, as in I get the general inflating folderA/folderB/fileX etc. However, I want to hold the code at the unzip command, waiting until the unzipping is complete. I have tried using sleep(5) but I don’t want to use this and just hope that it will always take less than five seconds especially this is would be inefficient for very small zipped

Sys.glob () within unzip ()

由 ￣綄美尐妖づ 提交于 2019-12-25 04:33:56
问题 TLDNR: How do I use Sys.glob () within unzip ()? I have multiple .zip files and I want to extract only one file from each archive. For example, one of the archives contains the following files: [1] "cmc-20150531.xml" "cmc-20150531.xsd" "cmc-20150531_cal.xml" "cmc-20150531_def.xml" "cmc-20150531_lab.xml" [6] "cmc-20150531_pre.xml" I want to extract the first file because it matches a pattern. In order to do that I use the following command: unzip("zip-archive.zip", files=Sys.glob("[a-z][a-z][a

From Default Perl on OSX, How To Unzip To Folder?

由 纵饮孤独 提交于 2019-12-25 01:46:35
问题 I'm trying to avoid having to include other libraries and keep this simple on OSX, using the default Perl that ships with OSX since Snow Leopard . I'm also trying to avoid shelling out to Bash to run the unzip. I found this example almost works, but dies on this line: my $fh = IO::File->new($destfile, "w") or die "Couldn't write to $destfile: $!"; with this error: Couldn't write to /tmp/mytest/Install Norton Security.localized//: Is a directory at test7.pl line 42. Previously, I zipped the
订阅 unzip