smtplib

问题 I have the following code import smtplib from email.mime.text import MIMEText smtpserver = 'smtp.gmail.com' AUTHREQUIRED = 1 # if you need to use SMTP AUTH set to 1 smtpuser = 'admin@myhost.com' # for SMTP AUTH, set SMTP username here smtppass = '123456' # for SMTP AUTH, set SMTP password here RECIPIENTS = ['online8@gmail.com'] SENDER = 'admin@myhost.com' msg = MIMEText('dsdsdsdsds\n') msg['Subject'] = 'The contents of iii' msg['From'] = 'admin@myhost.com' msg['To'] = ''online8@gmail.com''

问题 Traceback (most recent call last): s = smtplib.SMTP('localhost') File "/usr/lib/python2.7/smtplib.py", line 251, in __init__ (code, msg) = self.connect(host, port) File "/usr/lib/python2.7/smtplib.py", line 311, in connect self.sock = self._get_socket(host, port, self.timeout) File "/usr/lib/python2.7/smtplib.py", line 286, in _get_socket return socket.create_connection((host, port), timeout) File "/usr/lib/python2.7/socket.py", line 571, in create_connection raise err socket.error: [Errno

问题 I am trying to make an open SMTP relay using the new aiosmtpd library that replaces smtpd . The program below instantiates a Proxy handler that is passed onto the mail controller, which is started afterwards in the background. A message is then created with a standard smtplib client that connects to the relay. All is good until the SMTP conversation between the client and the relay ends with the message never leaving the relay. The relay never replies with a 250 OK\r\n and a ctrl+c shows that

问题 I've searched a fair bit on this and couldn't come up with anything satisfactory. I've been trying to write a python program to listen for email bounce reports and depending on the reason for the bounce resend them at different intervals. import smtplib from smtplib import * sender = 'foo@bar.com' receivers = ['42@life.com'] message = """From: From Arthur <foo@bar.com> To: To Deep Thought <42@life.com> Subject: SMTP e-mail test This is a test e-mail message. """ try: smtpObj = smtplib.SMTP(

问题 So I'm trying to send an email using python but I can't as long as it converts it to ASCII, is there a way around this or do I need to find another function? File "/usr/lib/python3.6/smtplib.py", line 855, in sendmail msg = _fix_eols(msg).encode('ascii') UnicodeEncodeError: 'ascii' codec can't encode character '\u2019' in position 1562: ordinal not in range(128) Can I get around this or do I have convert? and how would i convert? 回答1: Traditionally, SMTP requires the message you submit to be

问题 Without much prior knowledge of MIME, I tried to learned how to write a Python script to send an email with a file attachment. After cross-referencing Python documentation, Stack Overflow questions, and general web searching, I settled with the following code [1] and tested it to be working. import smtplib from email.MIMEMultipart import MIMEMultipart from email.MIMEText import MIMEText from email.MIMEBase import MIMEBase from email import encoders fromaddr = "YOUR EMAIL" toaddr = "EMAIL

问题 I was wondering. Is there any way to add multiple receivers in Python on its default SMTPlib? Like (subject and content set already, smtp server gmail.): python sendmail.py receiver1@gmail.com receiver2@gmail.com receiver3@gmail.com ... Thanks 回答1: Tested before posting! import smtplib from email.mime.text import MIMEText s = smtplib.SMTP('smtp.uk.xensource.com') s.set_debuglevel(1) msg = MIMEText("""body""") sender = 'me@example.com' recipients = ['john.doe@example.com', 'john.smith@example

问题 I am successfully able to send email using the smtplib module. But when the emial is sent, it does not include the subject in the email sent. import smtplib SERVER = <localhost> FROM = <from-address> TO = [<to-addres>] SUBJECT = "Hello!" message = "Test" TEXT = "This message was sent with Python's smtplib." server = smtplib.SMTP(SERVER) server.sendmail(FROM, TO, message) server.quit() How should I write "server.sendmail" to include the SUBJECT as well in the email sent. If I use, server

问题 I have been searching a lot and I still don't know how yo access variables from different classes in python. In this case I want to access the variable self.v from PageOne class to PageTwo class. Here is my code. import tkinter as tk import smtplib TITLE_FONT = ("Helvetica", 18, "bold") class SampleApp(tk.Tk): def __init__(self): tk.Tk.__init__(self) container = tk.Frame(self) container.pack(side="top", fill="both", expand=True) container.grid_rowconfigure(0, weight=1) container.grid

问题 I want to produce two HTML tables using tabulate package, but I am only able to produce one table and send mail. Is it possible to put more than one html table into a message sent with smtplib and email? Whenever I use attach() for more than one thing, it only adds the first. text = """ Hello, Friend. Here is your data: {table} Regards, Me """ html = """ <html> <body> <p>Hello, Friend.</p> <p>Here is your data:</p> {table} <p>Regards,</p> <p>Me</p> </body> </html> """ with open('input.csv')