smtplib

问题 I am trying to use the hotmail smtp server from python. However, my login attempt gives rise to an apparent SSL3 version number error. How can I change the version I am using and how do I even investigate this? >> s.connect('smtp.live.com:587') (220, 'BLU0-SMTP46.phx.gbl Microsoft ESMTP MAIL Service, Version: 6.0.3790.4675 ready at Tue, 2 Jul 2013 12:15:57 -0700') >> s.ehlo() (250, 'BLU0-SMTP46.phx.gbl Hello [123.456.789.01]\nTURN\nSIZE 41943040\nETRN\nPIPELINING\nDSN\nENHANCEDSTATUSCODES

问题 I am trying to use the hotmail smtp server from python. However, my login attempt gives rise to an apparent SSL3 version number error. How can I change the version I am using and how do I even investigate this? >> s.connect('smtp.live.com:587') (220, 'BLU0-SMTP46.phx.gbl Microsoft ESMTP MAIL Service, Version: 6.0.3790.4675 ready at Tue, 2 Jul 2013 12:15:57 -0700') >> s.ehlo() (250, 'BLU0-SMTP46.phx.gbl Hello [123.456.789.01]\nTURN\nSIZE 41943040\nETRN\nPIPELINING\nDSN\nENHANCEDSTATUSCODES

问题 I'm wondering if I can send out a matplotlib pyplot through smtplib. What I mean is, after I plot this dataframe: In [3]: dfa Out[3]: day imps clicks 70 2013-09-09 90739468 74609 69 2013-09-08 90945581 72529 68 2013-09-07 91861855 70869 In [6]: dfa.plot() Out[6]: <matplotlib.axes.AxesSubplot at 0x3f24da0> I know I can see the plot using plt.show() but where is the object itself stored? Or am I misunderstanding something about matplotlib? Is there a way to convert it to a picture or html

问题 This question already has answers here : How to send email attachments? (12 answers) Closed 5 years ago . So I'm trying to send a .txt file as an attachment and I can't find the right code to work. Here is my code: import pythoncom import win32gui import win32console import smtplib from email.mime.multipart import MIMEMultipart from email.mime.text import MIMEText fromaddr = 'zover1@gmail.com' toaddrs = 'zover2@gmail.com' msg = "contrl text file" username = 'zover1@gmail.com' password=

问题 My SendMail function looks like this: MY_SMTP = #I can't show it here def SendMail(authentication_data, email_from, email_to_list, email_cc_list, email_subject, email_message, list_file) user_name = authentication_data["name"] user_password = authentication_data["password"] msg = MIMEMultipart(email_message) server = smtplib.SMTP(MY_SMTP) server.starttls() emails_list_string = ", ".join(email_to_list) emails_cc_list_string = ", ".join(email_cc_list) msg["From"] = email_from msg["To"] = emails

问题 Lets say I have two clauses that I want to model in SMT, is it better to add them as separate assertions like (assert (> x y)) (assert (< y 2)) or to add one assertion with and operator like this (assert (and (> x y) (< y 2) )) Does this matter for large scale problems in terms of SMT solver performance. I am using Z3. 回答1: The conjunction gets split into multiple assertions, so it doesn't really matter too much. If you introduce a large conjunction, Z3's parser will create a term that

问题 I have read a few posts on this but I could not find help in them. I have a python script that sends mail using smtplib. It works when invoked from the command line. I have #!/usr/bin/python as the first row and can run it both using /home/pi/ipsender.py and python /home/pi/ipsender.py . My crontab is */1 * * * * /home/pi/ipsender.py but I have also tried */1 * * * * python /home/pi/ipsender.py and */1 * * * * /usr/bin/python /home/pi/ipsender.py . Doing which python I get /usr/bin/pyhton and

问题 I am trying to use smtplib for sending mails in python 2.7. The below code is pretty simple: import smtplib def main(argv=None): sender = 'abc@gmail.com' receivers = ['xyz@gmail.com'] message = """ This is a test e-mail message. """ smtpObj = smtplib.SMTP('xyz@gmail.com',25) smtpObj.login('abc', 'pwd') smtpObj.sendmail(sender, receivers, message) print "Successfully sent email" if __name__ == '__main__': main() Now when I execute the below code, I keep getting this exception: smtplib

问题 How do I capture the debug output from the Python smtplib library? Here is my test program: import smtplib s = smtplib.SMTP("mx10.comcast.com") s.set_debuglevel(1) s.sendmail("no-such-sender@comcast.com",["no-such-receiver@comcast.com"],""" from: no-such-sender@comcast.com to: no-such-receiver@comcast.com subject: no such message This message won't be delivered to anybody. """) Here is the output: send: 'ehlo dance.local\r\n' reply: '250-mx10.comcast.com says EHLO to 129.6.220.67:57015\r\n'

问题 I need to check the timeout of a SMTP-Server, but my socket just closes. What am I doing wrong? Here is my test for it: #!/usr/bin/python import smtplib import time import datetime import socket socket.setdefaulttimeout(1800) now = time.time() server = smtplib.SMTP() server.set_debuglevel(1) server.connect('mx.foo.bar','25') (code,resp) = server.docmd('NOOP') then = time.time() print then-now Lets hope this works. 回答1: Well, I haven't found any method to hold a smtp connection open with