slash

Handling escaped slashes in a JSON string

好久不见. 提交于 2019-12-13 17:26:39
问题 I'm trying to get the json of the database and the code goes like this $path["file_name"] = "www.119.com\/assets\/demo\/large\/".$row["file_name"]; While I convert to a json object and it shows like this. www.119.com\\\/assets\\\/demo\\\/large\\\/demo1.png I just applied \ to print special character / , but it's not working. I applied many things to print the special character. Is it a problem in converting special character to JSON? 回答1: As has been mentioned by others, a forward slash is

Trailing slash and initial www

六眼飞鱼酱① 提交于 2019-12-13 14:21:59
问题 I have this htaccess: RewriteEngine On # redirect with www RewriteCond %{HTTP_HOST} ^mydomain [NC] RewriteRule ^(.*)$ http://www.%{HTTP_HOST}/$1/ [R=301,L] # add .php internally RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ $1.php [L,QSA] So my .php files can be called without the .php extension. But I'd like them to be called only with a trailing slash. So when this trailing slash is not given, it should be appended with a 301. The problem I have

How to escape slashes in command line argument (file path) in Java?

妖精的绣舞 提交于 2019-12-11 12:17:23
问题 Please note I'm developing this using NetBeans under Windows. I'm also running JDK 1.8. The program takes a few arguments, via the command-line. One argument is a file path. The user might type -i C:\test . How do I escape the slash? Nothing seems to work right. public class Test { public static void main(String[] args) throws FileNotFoundException, ParseException { // Simulate command line execution String[] arguments = new String[] { "-i C:\test" }; // Create Options object Options options

Trailing Slash Behavior in Rails Application

不羁的心 提交于 2019-12-11 07:44:11
问题 I am currently trying to mimic folder/files behavior in rails with category/articles schema. So, I have this in routes : match '/:category/' => 'category#list_articles' match '/:category/:article.:format' => 'article#show' Basically, request urls are : http://www.example.com/category/ http://www.example.com/category/article.html Everything works. The problem is it's working to well. An url like http://www.example.com/category (without the trailing slash) serves also the list of articles. Does

cannot keep backslash in string in ruby code

爱⌒轻易说出口 提交于 2019-12-11 07:21:56
问题 I have a string in my ruby code which ends with a backslash: acc.secret_key = "ASJSJJDSJFJJFFJJFJF\" acc.save Above is the code snippet, when I try to save it using Active record I get an error, I tried adding another slash that is acc.secret_key = "ASJSJJDSJFJJFFJJFJF\\" acc.save But now I have two slashes in the DB. What am I missing? THanks a lot. 回答1: Are you seeing this in the console? If thats the case you're just seeing the escaping not two actual backslashes. string = "1234\\" # =>

Need some answer about example.php/example

爱⌒轻易说出口 提交于 2019-12-11 05:13:07
问题 I am doing on a project and i stumble upon on this while going through some code. I had tried to google but could not find a correct keyword to search regarding this question. http://www.fruit.com/example.php/red I am confuse with this and the end of a .php it still have a character /red for example. What is the purpose of this? Does it have something to do with POST method? 回答1: A possible explanation is that the developer is using .htaccess rewrite rules. It is most likely extra data that

In Python, how should one extract the second-last directory name in a path?

主宰稳场 提交于 2019-12-10 13:24:54
问题 I have a string like the following: /cvmfs/atlas.cern.ch/repo/sw/ASG/AnalysisTop/2.0.24/RootCore How should I extract the "2.0.24" from this string? I'm not sure how to split the string using the slashes (in order to extract the second last element of the resultant list) and I'm not sure if this would be a good approach. What I have right now is the following: "/cvmfs/atlas.cern.ch/repo/sw/ASG/AnalysisTop/2.0.24/RootCore".split("/RootCore")[0].split("AnalysisTop/")[1] 回答1: '/cvmfs/atlas.cern

Escaping backslash in Postgresql

天涯浪子 提交于 2019-12-10 04:35:16
问题 I'm trying to write an sql function in Postgresql that will parse a file path. I want to return just the file name. I cannot get past getting an accurate text string in the function. Here is the function: Function: job_page("inputText" text) DECLARE $5 text; BEGIN $5 = quote_literal("inputText"); return $5; END When I run this: select job_page('\\CAD_SVR\CADJOBS\7512-CEDARHURST ELEMENTARY SCHOOL\7512-20.DWG') I get this result: "E'\\CAD_SVRCADJOBSé2-CEDARHURST ELEMENTARY SCHOOLé2-20.DWG'"

How to remove multiple trailing slashes?

心不动则不痛 提交于 2019-12-09 23:58:50
问题 Here are my rewrite rules: ########### # Rewrite # ########### # Settings RewriteEngine On RewriteBase / # Cache Busting RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_URI} "^(.+)\.\d+\.(css|js)$" [NC] RewriteRule "^.*$" "/%1.%2" [L] # No Index RewriteCond %{THE_REQUEST} "\ /.*index\.php.*\ " [NC] RewriteRule "^(.*)index\..+$" "/$1" [L,NC,R=301] # No Question Mark RewriteCond %{THE_REQUEST} "\ /[^?]*\?\ " RewriteRule "^(.*)$" "/$1?" [L,R=301] #

Bash - check for a string in file path

折月煮酒 提交于 2019-12-08 15:22:22
问题 How can I check for a string in a file path in bash? I am trying: if [[$(echo "${filePathVar}" | sed 's#//#:#g#') == *"File.java"* ]] to replace all forward slashes with a colon (:) in the path. It's not working. Bash is seeing the file path string as a file path and throws the error "No such file or directory". The intention is for it to see the file path as a string. Example: filePathVar could be **/myloc/src/File.java in which case the check should return true. Please note that I am