seconds

问题 Lets say i have long currentMillis and long oldMillis. The difference between the two timestamps is very tiny and always less than 1 second. If i want to know the difference between the timestamps in milleseconds, i can do the following: long difference = currentmillis-oldmillis; And if i want to convert difference to seconds, i can just divide it by 1000. However if the difference in milliseconds is less than 1000 milliseconds(<1 second), dividing it by 1000 will result in 0. How can i get

问题 Currently I am working with a big dataframe (12x47800). One of the twelve columns is a column consisting of an integer number of seconds. I want to change this column to a column consisting of a datetime.time format. Schedule is my dataframe where I try changing the column named 'depTime'. Since I want it to be a datetime.time and it could cross midnight i added the if-statement. This 'works' but really slow as one could imagine. Is there a faster way to do this? My current code, the only one

问题 Soundcloud's API gives the duration of it's tracks as milliseconds. JSON looks like this: "duration": 298999 I've tried many functions I found on here to no avail. I'm just looking for something to convert that number to something like looks like this: 4:59 Here's one that got close, but doesn't work. It doesn't stop the seconds at 60. It goes all the way to 99 which makes no sense. Try entering "187810" as a value of ms, for example. var ms = 298999, min = Math.floor((ms/1000/60) << 0), sec

问题 This question already has answers here : Convert timestamp in milliseconds to string formatted time in Java (9 answers) Closed 2 years ago . I Have the following code in my application System.out.println(rec.getDateTrami().getTime()); I need to convert the following format (I suppose that they are seconds) 43782000 29382000 29382000 To a format YYYY-MM-DD HH24:MI:SS , anyone can help to me? 回答1: You can make use of the SimpleDateFormat Example: SimpleDateFormat format = new SimpleDateFormat(

问题 This is not a duplicate question, but involves a little understanding about time. I need a solution to the following problem I have a number of specifically produced times (based on a date), that need to be rounded to the nearest 15 secs: 60 secs is 1 minute meaning a regular round, floor, ceiling is to the nearest decimal (10/5) which doesn't help me with time. also since I'm dealing with secs, it could be that 59:59 will be rounded up to the nearest hour: e.g. 17:59:59 should be 18:00.

问题 I have a pandas dataFrame called 'df' as follows value 2015-09-27 03:58:30 1.0 2015-09-27 03:59:30 1.0 2015-09-27 04:00:30 1.0 2015-09-27 04:01:30 1.0 I just want to strip out the seconds to get this value 2015-09-27 03:58:00 1.0 2015-09-27 03:59:00 1.0 2015-09-27 04:00:00 1.0 2015-09-27 04:01:00 1.0 How can i do this? ive tried things like df.index.to_series().apply(datetime.replace(second=0, microsecond=0)) but i always get errors TypeError: descriptor 'replace' of 'datetime.datetime'

问题 This question already has an answer here : Linux task schedule to Hour, minute, second (1 answer) Closed 5 years ago . I just want to run a shell scrip at say this exact time "16:22:36". utilities like "at" are useless since they don't have "seconds". "sleep" does not work since the loop is ending 8 hours ahead of time for some reason :s , I have searched all over google and couldn't find any tools. so a huge Os like Linux doesn't have a proper task scheduler? 回答1: The standard cron lacks

问题 I've tried different methods around the web but couldn't make it work. Cursor cursor = sqlite.myDataBase.rawQuery("SELECT StartDate, EndDate FROM Tracks Where Id="+'"'+trackId+'"',null); SimpleDateFormat outputFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); Date startDate = outputFormat.parse(cursor.getString(cursor.getColumnIndex("StartDate"))); Date endDate = outputFormat.parse(cursor.getString(cursor.getColumnIndex("EndDate"))); In this way I get both dates in good format. Now I want

问题 I'm learing Python and Pygame, and my first thing I'm making is a simple Snake game. I'm trying to make it so that the snake moves once every 0.25 seconds. Here is the part of my code that loops: while True: check_for_quit() clear_screen() draw_snake() draw_food() check_for_direction_change() move_snake() #How do I make it so that this loop runs at normal speed, but move_snake() only executes once every 0.25 seconds? pygame.display.update() I want all of the other function to run normally,

问题 like i have 5 Times 1. 05:12:02 2. 19:12:52 3. 40:12:14 4. 56:54:10 5. 41:12:12 ----------- Total Seconds : 0#####..` ----------- i want like this, how can i , please help me . can I use this? : public String addTime(int hour, int minute, int minutesToAdd) { Calendar calendar = new GregorianCalendar(1990, 1, 1, hour, minute); calendar.add(Calendar.MINUTE, minutesToAdd); SimpleDateFormat sdf = new SimpleDateFormat("HH:mm"); String date = sdf.format(calendar.getTime()); return date; } 回答1: A