seconds | 易学教程

sql中两个时间类型相减得到的值

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【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> 今天有人把数据库两个time类型的字段查出来并做了减法，得到一个长形的数字。这个数字是什么？首先在数据库里建立一张test表（mysql的数据库） CREATE TABLE `NewTable` ( `id` int(10) NOT NULL AUTO_INCREMENT , `time1` timestamp NULL DEFAULT NULL ON UPDATE CURRENT_TIMESTAMP , `time2` timestamp NULL DEFAULT NULL , PRIMARY KEY (`id`) ) 然后录入两条数据，用如下语句查询 SELECT time2,time1,time2-time1 FROM `test`; 查询结果如下，结论是这个差值1的单位貌似是秒。 2012-05-15 19:02:17 2012-05-15 19:02:16 1 把time1和time2的类型改成date。这个结果的单位是0. 把time1和time2的类型改成datetime，这个结果如下，貌似单位还是秒。 2012-05-15 19:02:16 2012-05-15 19:02:17 -1.000000 今天遇到的数字结果不确定的情形并没有复现，难道数据库是因为数据库的类型是oracle？

Android Studio: Add number every Second

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问题 I want to display the income of a person in a certain time. For this I ask for the income per month (=gehalt) and working hours per week (stunden) in another activity. Then in the second activity I want to increase the TextView showGehaltproSekunde (id = textViewZahl) every second by the income per second. I am a beginner, so I don't know what exactly I have to write in public void run(). Or is there another possibility to increase the number every second? I hope someone can help me. Thank

Haskell: How to pretty print number of seconds as a date and time?

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问题 I have an integral value that is the number of seconds since the Epoch. I can output it as a big integer, but I want to show it as a human-readable date and time. For example: secToTimestamp :: Int32 -> [Char] which returns something like: 2016-01-01 14:11:11 回答1: In the interests of having a simple time based solution (since time is the defacto module for manipulating anything time related): import Data.Time.Clock.POSIX import Data.Time.Format secToTimestamp :: Int32 -> String secToTimestamp

Convert double to struct tm

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问题 I have a double containing seconds. I would like to convert this into a struct tm . I can't find a standard function which accomplishes this. Do I have to fill out the struct tm by hand? I just accidentally asked this about converting to a time_t and http://www.StackOverflow.com will not let me post unless I link it. 回答1: Well, you accidentally asked the right question before. Convert double to time_t , and then convert that to a struct tm . There's no subsecond field in struct tm anyway. 回答2

Converting Seconds to Time Format

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问题 I am trying to find a good solution for converting seconds to time format. I have this function which works fine for my needs so far. function secondstotime(secs) { var t = new Date(1970,0,1); t.setSeconds(secs); var s = t.toTimeString().substr(0,8); if(secs > 86399) s = Math.floor((t - Date.parse("1/1/70")) / 3600000) + s.substr(2); return s; } alert(secondstotime(1920)); So you can run this in jsfiddle http://jsfiddle.net/7Pp5z/ So this works great and works for hours etc but i am looking

Objective-C: Adding 10 seconds to timer in SpriteKit

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问题 I used someone else's code for writing a timer in SpriteKit, and tweaked it a bit. Here's what my code looks like: - (void)createTimerWithDuration:(NSInteger)seconds position:(CGPoint)position andSize:(CGFloat)size { // Allocate/initialize the label node. _countdownClock = [SKLabelNode labelNodeWithFontNamed:@"Avenir-Black"]; _countdownClock.fontColor = [SKColor blackColor]; _countdownClock.position = position; _countdownClock.horizontalAlignmentMode = SKLabelHorizontalAlignmentModeLeft;

Ruby/Rails - How to convert seconds to time?

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问题 I need to perform the following conversion: 0 -> 12.00AM 1800 -> 12.30AM 3600 -> 01.00AM ... 82800 -> 11.00PM 84600 -> 11.30PM I came up with this: (0..84600).step(1800){|n| puts "#{n.to_s} #{Time.at(n).strftime("%I:%M%p")}"} which gives me the wrong time, because Time.at(n) expects n to be number of seconds from epoch: 0 -> 07:00PM 1800 -> 07:30PM 3600 -> 08:00PM ... 82800 -> 06:00PM 84600 -> 06:30PM What would be the most optimal, time zone independent solution for this transformation? 回答1:

.NET constant for number of seconds in a day?

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问题 Does .NET have a constant for the number of seconds in a day (86400)? 回答1: If you want readability you could use: (new TimeSpan(1,0,0,0)).TotalSeconds though just using your own const might be clearer :) 回答2: It's not a constant value http://en.wikipedia.org/wiki/Leap_second 回答3: Number of seconds in a regular day is 86400. But the days when DST changes happen may be shorter or longer. However, writing 24*60*60 is not a bad practice at all, and it is most likely to be in-lined by the compiler

Convert Seconds to datetime timedelta [duplicate]

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问题 This question already has answers here : How do I convert seconds to hours, minutes and seconds? (10 answers) Closed 5 years ago . In python how can I simply convert an integer of seconds into (h:m:s) using the datetime module? i.e. 500000 ---> 138:53:20 Please, no tuple hackery. 回答1: Maybe this answer from SO will do: >>> import datetime >>> str(datetime.timedelta(seconds=500000)) '5 days, 18:53:20' 来源： https://stackoverflow.com/questions/25193464/convert-seconds-to-datetime-timedelta

Number of seconds since the beginning of the day UTC timezone

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问题 How do I find "number of seconds since the beginning of the day UTC timezone" in Python? I looked at the docs and didn't understand how to get this using datetime.timedelta . 回答1: Here's one way to do it. from datetime import datetime, time utcnow = datetime.utcnow() midnight_utc = datetime.combine(utcnow.date(), time(0)) delta = utcnow - midnight_utc print delta.seconds # <-- careful EDIT As suggested, if you want microsecond precision, or potentially crossing a 24-hour period (i.e. delta