问题
Lets say i have long currentMillis and long oldMillis. The difference between the two timestamps is very tiny and always less than 1 second.
If i want to know the difference between the timestamps in milleseconds, i can do the following:
long difference = currentmillis-oldmillis;
And if i want to convert difference to seconds, i can just divide it by 1000. However if the difference in milliseconds is less than 1000 milliseconds(<1 second), dividing it by 1000 will result in 0.
How can i get the difference between the two timestamps if the difference is less than a second? For example, if the difference is 500 milliseconds, the desired output is 0.5 seconds.
Using float/double instead of long always returns 0.0 for some reason i don't understand.
My code:
private long oldmillis = 0, difference = 0;
private long calculateDifference()
{
long currentMillis = System.currentTimeMillis();
if (oldMillis == 0) oldMillis = currentMillis;
difference = currentMillis - oldMillis;
oldMillis = currentMillis;
return difference;
}
The method calculateDifference is called randomly with a small random time interval.
回答1:
It sounds like you just need to convert the results into double
before the division:
// This will work
double differenceMillis = currentMillis - oldMillis;
double differenceSeconds = differenceMillis / 1000;
// This will *not* work
double differenceSecondsBroken = (currentMillis - oldMillis) / 1000;
In the latter code, the division is performed using integer arithmetic, so you'll end up with a result of 0 that is then converted to a double
.
An alternative which would work is to divide by 1000.0, which would force the arithmetic to be done using floating point:
double differenceSeconds = (currentMillis - oldMillis) / 1000.0;
来源:https://stackoverflow.com/questions/24168492/java-how-to-get-the-difference-between-currentmillis-and-a-timestamp-in-the-past