scientific-notation

问题 I'm currently stuck on a Codewars challenge that I can't get my head around: Given a string representation of two integers, return the string representation of those integers, e.g. sumStrings('1','2') // => '3' I've used the following code so far, but it fails on large number test cases as the number is converted into a scientific notation: function sumStrings(a,b) { var res = +a + +b; return res.toString(); } Any help would be much appreciated. Edit: Fiddle example: https://jsfiddle.net

问题 I have a SQL statement which is exporting data to Excel. The problem is that large numbers get converted to scientific notation when exported to Excel. To avoid that I am using char(39), i.e. single quotes around the number. In addition, also checking for null value so using ISNULL . ISNULL(char(39) + Rtrim([NumberCol]) + char(39), '') [NumberCol] has char datatype So now if NumberCol is a numeric value I get '000123456789' format which is what I want. But when it is Null then I get ''. I do

问题 I have a double and i am trying to convert it to a decimal. When i use decimalformat to achieve this i get the following: public void roundNumber(){ double d = 2.081641999208976E-4; JOptionPane.showMessageDialog(null,roundFiveDecimals(d)); } public double roundFiveDecimals(double d) { DecimalFormat df = new DecimalFormat("#.#####"); return Double.valueOf(df.format(d)); } I want the output to be .00021; however, i get 2.1E-4. Can anyone help explain how to get .00021 and not 2.1E-4? 回答1: You

问题 How can I read data in scientific notation (D+) format into R? e.g. -0.416932D+01, -0.412300D+02 回答1: Solution using stringr package: library(stringr) x <- c("-0.416932D+03") as.numeric(str_replace(x, "D", "e")) [1] -416.932 If you prefer not to use external packages, you can use the gsub function from the base package: as.numeric(gsub("D","e",x)) 来源： https://stackoverflow.com/questions/29166012/reading-scientific-notation-d

问题 I would like to combine an array full of floats with an array full of strings. Is there a way to do this? (I am also having trouble rounding my floats, insert is changing them to scientific notation; I am unable to reproduce this with a small example) A=np.array([[1/3,257/35],[3,4],[5,6]],dtype=float) B=np.array([7,8,9],dtype=float) C=np.insert(A,A.shape[1],B,axis=1) print(np.arround(B,decimals=2)) D=np.array(['name1','name2','name3']) How do I append D onto the end of C in the same way that

问题 I'm looking for an elegant solution here (if one exists). I've got a bunch of numbers, with an arbitrary amount of decimal places. I want to force the number to use 8 decimal places if it's got more than 8 trailing zeroes i.e. 0.000000004321 That would be converted to: 0.00000001 But I don't want to use number format because if I force it to 8 decimals with number format my numbers without 8 decimal places will look like: 1.00000000 I'd rather these just look like (for amounts >= 1): 1

问题 I've searched for this answer but cannot find anything for VBS. For instance: dim num num = 1234567890123456 'a 16 digit number msgbox num Working with num in any way will result in the number being displayed in scientific notation. How can I avoid this? 回答1: The 16 digit number is changed to a Double by VBScript because neither Int , nor Long can store that number. You can use the FormatNumber function to display it as an integer: FormatNumber(Expression, NumDigitsAfterDecimal,

问题 Float or double always gives answer in scientific notation if number of digits are 7 or more. Like an decimal number 10000000.5 it is giving 1e-08 something. I am wondering if we can print 10000000.5 without adding any new header file. 回答1: If you are printing to cout , use std::cout.setf( std::ios::fixed, std::ios::floatfield ); See it work. You might also want std::cout.precision(1) to set the number of digits after the decimal point. 回答2: printf("%.1f", someFloat) should do that for you,

问题 I would like to have a function in python that can handle a diverse range of numbers from very large to very small and even large numbers with a small fraction right of the decimal (see code below). I need to convert the number to a string and remove any scientific notation it may have. I also need to remove trailing zeros right of the decimal point. This is the closest solution I have so far and it works for most numbers, but not all as you can see. Are there any improvements that can be

问题 I'm having a bit of trouble with getting awk to read scientific notation from a file, here is some example input: #Plane Turn Real Imaginary HOR 1 0.0000e+00 -2.1885e-07 HOR 1 4.8481e-08 -8.1221e-08 HOR 1 4.0934e-08 -6.0784e-08 HOR 1 3.5707e-08 -5.1223e-08 HOR 1 3.1664e-08 -4.5608e-08 HOR 1 2.8268e-08 -4.1964e-08 HOR 1 2.5242e-08 -3.9469e-08 HOR 1 2.2429e-08 -3.7707e-08 HOR 1 1.9731e-08 -3.6430e-08 HOR 1 1.7082e-08 -3.5479e-08 I'm using awk to format this file for plotting with gnuplot using