resteasy

Using JAX-RS (RESTEasy) as middleware: brokering a client's request to another server

大兔子大兔子 提交于 2020-01-15 15:12:20
问题 I'm building a server using JAX-RS (RESTEasy) that will provide a REST interface to clients. The server will act as a broker between the client and another server. The other server, a 3rd-party server (JasperReports), also has a REST interface. I'd like to use JAX-RS to have my broker talk to that server. (My broker server adds authentication and other services.) So, there you have the three parties: client, broker-server, reports-server. I see the workflow this way. The broker-server

Using JAX-RS (RESTEasy) as middleware: brokering a client's request to another server

北城以北 提交于 2020-01-15 15:12:10
问题 I'm building a server using JAX-RS (RESTEasy) that will provide a REST interface to clients. The server will act as a broker between the client and another server. The other server, a 3rd-party server (JasperReports), also has a REST interface. I'd like to use JAX-RS to have my broker talk to that server. (My broker server adds authentication and other services.) So, there you have the three parties: client, broker-server, reports-server. I see the workflow this way. The broker-server

Global custom exception handler in resteasy

99封情书 提交于 2020-01-13 10:14:13
问题 Is it possible to make global exception handler for all unexpected errors. Because it's impossible to make all possible classes like this: public class ExceptionHandler implements ExceptionMapper<JsonMappingException> {...} I want something like this: public class ExceptionHandler implements ExceptionMapper<Exception> 回答1: You could probably do the following: @Provider public class GlobalExceptionHandler implements ExceptionMapper<Exception> { public Response toResponse(Exception exception) {

Can Swagger JaxRS do ApiModel Inheritance with discriminator?

荒凉一梦 提交于 2020-01-13 02:30:35
问题 I've tried with the Swagger JaxRs current master 1.0, and the devel_2.0 branch for Swagger 2.0. @ApiModel(value = "Animal", subTypes = {Dog.class, Lion.class}, discriminator = "type") public class Animal { @ApiModelProperty(value = "the discriminator field.") private String type; And here is one of the sub classes, @ApiModel(value = "Lion", parent = Animal.class) public class Lion { @ApiModelProperty(value = "the discriminator field.") private String type; I haven't found any many examples of

How to generate WADL file?

断了今生、忘了曾经 提交于 2020-01-12 10:49:53
问题 I wrote RESTful web service using RESTeasy implementation and turn EJB into JSON. And now I'm on the way of development client side. I'm using Netbeans. How I can generate WADL file? And after I would generated client stub without any problem. Please, could you suggest me how I can do this? Or maybe you know different easy way. Thanks a lot! Artem 回答1: Just FYI if you are trying to create a RESTful system, then generating client proxies using WADL will eliminate a significant number of the

Rest easy and init params - how to access?

*爱你&永不变心* 提交于 2020-01-11 08:45:22
问题 I'd like to have some init params in my web.xml and retrieve them later in the application, I know I can do this when I have a normal servlet. However with resteasy I configure HttpServletDispatcher to be my default servlet so I'm not quite sure how I can access this from my rest resource. This might be completely simple or I might need to use a different approach, either way it would be good to know what you guys think. Following is my web.xml, <web-app xmlns:xsi="http://www.w3.org/2001

Logging json posts with resteasy

人盡茶涼 提交于 2020-01-11 08:36:09
问题 I'm looking for a way to log JSON posts in a RESTEASY framework. I woul like to log the POST body to log file to see what the client is sending to me. Is there any interceptor or something similar that I can use, I have found an example for PreProcessInterceptor but it looks like it is deprecated. I'm using resteasy 3.0.8 回答1: You can use a ContainerRequestFilter: @Provider public class LogFilter implements ContainerRequestFilter { private Logger LOG = LoggerFactory.getLogger(LogFilter.class)

How configure Spring-Boot app to continue to use RestEasy?

隐身守侯 提交于 2020-01-11 02:32:10
问题 I have an old web application (pure servlet, without Spring) that I want to run as fat-jar. This app provides a lot of REST services. I don't want to modified old code. How configure Spring-Boot app to continue to use RestEasy? 回答1: You can use RESTEasy Spring Boot starter. Here is how you do it: Adding POM dependency Add the Maven dependency below to your Spring Boot application pom file. <dependency> <groupId>com.paypal.springboot</groupId> <artifactId>resteasy-spring-boot-starter<

如何使用Firefox或Chrome手动触发HTTP POST请求? [关闭]

走远了吗. 提交于 2020-01-06 23:19:46
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> 我想在我正在处理的Web应用程序上测试一些URL。 为此,我想手动创建HTTP POST请求(这意味着我可以添加我喜欢的任何参数)。 我缺少Chrome和/或Firefox中的任何扩展程序或功能吗? #1楼 对于firefox,还有一个名为RESTClient的扩展,非常好用: https://addons.mozilla.org/en-US/firefox/addon/restclient #2楼 CURL 很棒,可以做你想要的! 这是一个简单但有效的命令行工具。 其余实现测试命令: curl -i -X GET http://rest-api.io/items curl -i -X GET http://rest-api.io/items/5069b47aa892630aae059584 curl -i -X DELETE http://rest-api.io/items/5069b47aa892630aae059584 curl -i -X POST -H 'Content-Type: application/json' -d '{"name": "New item", "year": "2009"}' http://rest-api.io/items curl -i -X PUT -H 'Content

RESTEasy support for JAX-RS @RolesAllowed

时光总嘲笑我的痴心妄想 提交于 2020-01-06 04:24:46
问题 I've spend hours installing a custom login service in embedded Jetty 9.1.0.v20131115 and RESTEasy 3.0.5.Final. My login service will look users up in a database and assign them roles. It looks something like this: final Constraint restConstraint = new Constraint(); restConstraint.setName(Constraint.__BASIC_AUTH); restConstraint.setRoles(new String[]{"user", "admin"); restConstraint.setAuthenticate(true); final ConstraintMapping restConstraintMapping = new ConstraintMapping();