relative

Python import module from sibling folder

由 試著忘記壹切 提交于 2019-11-27 01:55:48
I have gone through many Python relative import questions but I can't understand the issue/get it to work... My Directory structure is: Driver.py A/ Account.py __init__.py B/ Test.py __init__.py ==================== Driver.py from B import Test ========= Account.py class Account: def __init__(self): self.money = 0 ==================== Test.py from ..A import Account ================== When I try to run python Driver.py I get the error Traceback (most recent call last): from B import Test File "B/Test.py", line 1, in <module> from ..A import Account ValueError: Attempted relative import beyond

IE7 relative/absolute positioning bug with dynamically modified page content

由 这一生的挚爱 提交于 2019-11-27 00:31:20
I was wondering if there's anyone having an idea how to tackle with the following problem in IE7: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>IE7 absolute positioning bug</title> <style type="text/css"> #panel { position: relative; border: solid 1px black; } #spacer { height: 100px; } #footer { position: absolute; bottom: 0px; } </style> <script type="text/javascript"> function toggle() { var spacer = document.getElementById("spacer"); var style = "block"; if

How to refer to relative paths of resources when working with a code repository in Python

由 扶醉桌前 提交于 2019-11-26 14:52:39
We are working with a code repository which is deployed both to Windows and Linux - sometimes on different directories. How should one of the modules inside the project refer to one of the non-Python resources in the project (CSV files, etc.)? If we do something like: thefile=open('test.csv') or: thefile=open('../somedirectory/test.csv') It will work only when the script is run from one specific directory, or a subset of the directories. What I would like to do is something like: path=getBasePathOfProject()+'/somedirectory/test.csv' thefile=open(path) Is this the right way? Is it possible?
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