relative

I've looked around the web for this before, and I suspect the answer is "you can't", but since I've not yet found an answer which is that definitive, I think it's worth asking here. The closest I've found touching on the problem is The mystery of the trailing slash and the relative url (which is currently down, but Google has a text-only cached version ). Because of the traditional design of URLs with a trailing slash being interpreted as a directory and those without a trailing slash being interpreted as a file resource, and relative URLs working off the directory, then if the current page

We have a Flash Builder (which is based on Eclipse) project that pulls source from different locations, included in the source control in which the project is. As per our organization requirements, the source code is present in directories not directly under the project directory. Initially we had the problem that all paths to the linked resources were absolute and did not work on other machines with different paths. Right now, the solution we have for this is to set up a Linked Resource Path Variable that points to the root of the working folder. All other locations are based on that, so we

I'm trying to get this line in my web.config file to use a relative path instead of hardcoded one, but nothing seems to be working. I can only find stuff for SQL and mySQL DBs <connectionStrings> <add name="dbConnection" connectionString="Provider=Microsoft.ACE.OLEDB.12.0;Data Source=C:\Users\Mike\Desktop\GeauxEat NEW\GeauxEat\App_Data\GeauxEatAccessDB.accdb"/> </connectionStrings> I tried making it <add name="dbConnection" connectionString="Provider=Microsoft.ACE.OLEDB.12.0;Data Source=|Data Directory|\GeauxEatAccessDB.accdb"/> but then it looks for something in this folder where it doesn't

Given handle of a Win32 window, I need to find position of it relative to its parent window. I know several functions (e.g.; GetWindowRect() and GetClientRect() ), but none of them explicitly return the desired coordinates. How do I do this? The solution is using the combined power of GetWindowRect() and MapWindowPoints() . GetWindowRect() retrieves the coordinates of a window relative to the entire screen area you see on your monitor. We need to convert these absolute coordinates into relative coordinates of our main window area. The MapWindowPoints() transforms the coordinates given relative

Lets say you have a module which contains myfile = open('test.txt', 'r') And the 'test.txt' file is in the same folder. If you'll run the module, the file will be opened successfully. Now lets say you import that module from another one which is in another folder. The file won't be searched in the same folder as the module where that code is. So how to make the module search files with relative paths in the same folder first? There are various solutions by using " __file__ " or " os.getcwd() ", but I'm hoping there's a cleaner way, like same special character in the string you pass to open()

Hey all -- I am pulling my hair out with relative imports in Python. I've read the documentation 30 times and numerous posts here on SO and other forums -- still doesn't seem to work. My directory structure currently looks like this src/ __init__.py main.py components/ __init__.py expander.py language_id.py utilities/ __init__.py functions.py I want expander.py and language_id.py to have access to the functions module. I run python main.py which accesses the modules just fine with from components.expander import * and components.language_id import *. However, the code inside expander and

stuff/ __init__.py mylib.py Foo/ __init__.py main.py foo/ __init__.py script.py script.py wants to import mylib.py This is just an example, but really I just want to do a relative import of a module in a parent directory. I've tried various things and get this error... Attempted relative import beyond toplevel package I read somewhere that the script from where the program starts shouldn't in the package, and I tried modifying the structure for that like so... stuff/ mylib.py foo.py // equivalent of main.py in above foo/ __init__.py script.py but got same error. How can I accomplish this? Is

I have the following directory: mydirectory ├── __init__.py ├── file1.py └── file2.py I have a function f defined in file1.py. If, in file2.py, I do from .file1 import f I get the following error: SystemError: Parent module '' not loaded, cannot perform relative import Why? And how to make it work? since file1 and file2 are in the same directory, you don't even need to have an __init__.py file. If you're going to be scaling up, then leave it there. To import something in a file in the same directory, just do like this from file1 import f i.e., you don't need to do the relative path .file1

I have 3 levels of div : (In green below) A top level div with overflow: hidden . This is because I want some content (not shown here) inside that box to cropped if it exceeds the size of the box. (In red below) Inside this, I have div with position: relative . The only use for this is for the next level. (In blue below) Finally a div I take out of the flow with position: absolute but that I want positioned relative to the red div (not to the page). I'd like to have the blue box be taken out of the flow and expand beyond the green box, but be positioned relative to the red box as in: However,

Hello I am trying to do a web application and have a problem: I don't know how to open a text file with Java that is saved in the resource folder: String relativeWebPath ="/src/main/resources/words.txt"; //Import der des Textdoumentes String absoluteDiskPath = getServletContext().getRealPath(relativeWebPath); File f = new File(absoluteDiskPath); (The file words.txt) As you can see on the image I am trying to access words.txt but it isn't working. Any ideas? Try this. InputStream is = getClass().getClassLoader() .getResourceAsStream("/words.txt"); BufferedReader br = new BufferedReader(new