relationship

java neo4j check if a relationship exist

点点圈 提交于 2019-12-11 02:27:40
问题 excluse if this is a duplicate, although I did not find the answer so far. I have an application that creates nodes and relationships via cypher statement against the REST-API. I create relationships with the below code: public URI createRelationship(GraphNodeTypes sourceType, URI sourceNode, GraphNodeTypes targetType, URI targetNode, GraphRelationshipTypes relationshipType, String[] jsonAttributes) { URI relationShipLocation = null; String cypherArt = getNodeIdFromLocation(sourceNode)+"-[:"

In Java what is the relationship of an anonymous class to the type it is defined as?

我们两清 提交于 2019-12-11 01:59:14
问题 If the anonymous class is defined as the type of an interface then the anonymous class implements the interface, however if it's defined as the type of another class (as shown below) it doesn't seem to extend the class (as I was told it did). public class AnonymousClassTest { // nested class private class NestedClass { String string = "Hello from nested class."; } // entry point public static void main (String args[]){ AnonymousClassTest act = new AnonymousClassTest(); act.performTest(); } //

What's the relationship between streamjs and linqjs

可紊 提交于 2019-12-11 01:29:29
问题 After reading SICP, I recently discovered streamjs. The developer referenced linqjs as an alternate implementation with different syntax, but I can't make the connection. How do the methods in streamjs map to those in linqjs? 回答1: I haven't used either library, but, here's my initial analysis (I've read quite a bit of SICP, but not the whole thing admittedly). stream.js is an implementation of a functional style data structure for a list. Many data structures in a functional language tend to

Update hasone relation behaves strangely (cakephp)

柔情痞子 提交于 2019-12-11 00:08:11
问题 I've got an existing Showcase that hasOne Gallery. The Gallery already exists with the foreignKey showcase_id set to the proper value. The Gallery has a text field that I try to update via the Showcase-controller. The result I get is an extra Gallery entry, along the original one, instead of an update of the original entry. What am I doing wrong? My Showcase-view looks as follows: echo $form->create('Showcase', array('action'=>'update')); echo $form->input('Showcase.id', array('type'=>'hidden

Get results from multiple tables based on relationship table

大兔子大兔子 提交于 2019-12-10 22:28:26
问题 I have dbo.Users tables Id, Name 1, John 2, Mary 3, Michael Then I have dbo.Phones table Id, Phonenumber 10, 1234 11, 5555 Then I have dbo.Relationship table Id, ChildId 1, 10 2, 11 How could I make a query that returns Id, Name, Phonenumber 1, John, 1234 2, Mary, 5555 3, Michael, NULL This is what I got so far. SELECT u.Id, u.Name, p.Phonenumber FROM dbo.Users as u LEFT JOIN dbo.Phones as p -- Something SQL Fiddle 回答1: Think of the Relationship table as the middle-man between your Users and

Laravel and Eloquent: Specifying columns in when retrieving related items

有些话、适合烂在心里 提交于 2019-12-10 19:17:03
问题 This is a followup post to: Laravel 4 and Eloquent: retrieving all records and all related records The solution given works great: $artists = Artist::with('instruments')->get(); return \View::make('artists')->withArtists($artists); It also works with just: $artists = Artist::get(); Now I'm trying to specify the exact columns to return for both tables. I've tried using select() in both the statement above and in my Class, like this: ArtistController.php $artists = Artist::select('firstname',

how do i avoid a circular relationship in my class diagram

时光怂恿深爱的人放手 提交于 2019-12-10 18:22:04
问题 Hi I have a question about some circular relationships that I am facing with my database design . I read a few more similar questions but couldn't solve my problem, so here is my class diagram : and here is the logic: A document belongs to a DocumentType ( invoice , order form , ..) a documentField ( date , address , nameClient , ... ) belongs to a documentType ( each documentType has its proper fields the FieldValue is the value of documentfield that will be saved in database it belongs to

Schema specified is not valid. Errors: 'System.Data.Spatial.DbGeography' which cannot be mapped to a primitive type

三世轮回 提交于 2019-12-10 17:11:38
问题 I'm doing Entity Framework (v6) db first. I get the following error when trying to access data from my datacontext. The relationship 'Model.FK_Table1_Table2' was not loaded because the type 'Model.Table1' is not available. The following information may be useful in resolving the previous error: The property 'Location' on the type 'Model.Table1' has a property type of 'System.Data.Spatial.DbGeography' which cannot be mapped to a primitive type. Any idea what is causing this error? 回答1: I don't

editing subdocments N-N relationship in mongodb

佐手、 提交于 2019-12-10 14:54:26
问题 I have an application where an article can be linked to multiple platforms . Article contains a list of platforms and platforms also contains a list of articles. For more detailed information please look at this stackoverflow question that I asked a few months ago. https://stackoverflow.com/a/40377383/5770147 The question was on how to create an article and implement the N-N relationship between article and platform. I have Creating article and Deleting the article setup so that the lists

why I can't access my 3rd level CoreData data in swift?

天涯浪子 提交于 2019-12-10 11:48:27
问题 I have this model: And In one of my ViewController classes I created a method with 3 do while loops (a nested loop) where I insert all the "cursos", "temas" and "subtemas" to populate all my coreData model. So, inside that method I put this loop to access a part of my coreData data to see if my nested loop work, I did it like this: var i = cursos.count var index = 0 do{ println(cursos[index].nombre) println(cursos[index].temas[0].nombre) println(cursos[index].temas[0].subTemas[0].nombre)