recurrence

We are to solve the recurrence relation through repeating substitution: T(n)=T(n-1)+logn I started the substitution and got the following. T(n)=T(n-2)+log(n)+log(n-1) By logarithm product rule, log(mn)=logm+logn, T(n)=T(n-2)+log[n*(n-1)] Continuing this, I get T(n)=T(n-k)+log[n*(n-1)*...*(n-k)] We know that the base case is T(1), so n-1=k -> k=n+1, and substituting this in we get T(n)=T(1)+log[n*(n-1)*...*1] Clearly n*(n-1)*...*1 = n! so, T(n)=T(1)+log(n!) I do not know how to solve beyond this point. Is the answer simply O(log(n!)) ? I have read other explanations saying that it is Θ(nlogn)

I'm tried to figure out how to do it for quite of time and its not working as intended; I'm writing a code where there is 1 to k numbers, I need to find all possible combination without repeats. e.g. for 3: 1, 2, 3, 12, 13. Example for counting 4-digits numbers with 1, 2, 3, 4, 5. int k = 5; for (int p = 0; p < k; p++) { for (int i = p+1; i < k; i++) { for (int j = i + 1; j < k; j++) { for (int h = j + 1; h < k; h++) { cout << p + 1 << i + 1 << j + 1 << h + 1 << endl; } } } } And there is example for 3-digits number with 1, 2, 3. int k = 4 for (int p = 0; p < k; p++) { for (int i = p+1; i < k;

Closed. This question is off-topic. It is not currently accepting answers. Learn more . Want to improve this question? Update the question so it's on-topic for Stack Overflow. I want to create a cron job that runs every x weeks and on a specific weekdays. for example: run every 2 weeks on midnight every Sunday and Monday. the cron expression is stored for every "plan" and i use ncrontab function in SQL Server 2008 to generate the dates of given cron expression. Is there an expression for it? or even join of several expressions? I've tried to use the following expression, but it always gives

I want to run this function everyday midnight to check expiry_date_notification. what can I do? I'm new to django and python. def check_expiry_date(request): products = Product.objects.all() for product in products: product_id = product.id expiry_date = product.expiry_date notification_days = product.notification_days check_date = int((expiry_date - datetime.datetime.today()).days) if notification_days <= check_date: notification = Notification(product_id=product_id) notification.save() As others have said, Celery can schedule tasks to execute at a specific time . from celery.schedules import