py4j

来源： https://stackoverflow.com/questions/64775753/how-to-run-arbitrary-ddl-sql-statements-or-stored-procedures-using-aws-glue

来源： https://stackoverflow.com/questions/64775753/how-to-run-arbitrary-ddl-sql-statements-or-stored-procedures-using-aws-glue

问题 I'm trying to do some testing on our JDBC driver using Python. Initially figuring out JPype, I eventually managed to connect the driver and execute select queries like so (reproducing a generalized snippet): from __future__ import print_function from jpype import * #Start JVM, attach the driver jar jvmpath = 'path/to/libjvm.so' classpath = 'path/to/JDBC_Driver.jar' startJVM(jvmpath, '-ea', '-Djava.class.path=' + classpath) # Magic line 1 driver = JPackage('sql').Our_Driver # Initiating a

问题 I'm trying to do some testing on our JDBC driver using Python. Initially figuring out JPype, I eventually managed to connect the driver and execute select queries like so (reproducing a generalized snippet): from __future__ import print_function from jpype import * #Start JVM, attach the driver jar jvmpath = 'path/to/libjvm.so' classpath = 'path/to/JDBC_Driver.jar' startJVM(jvmpath, '-ea', '-Djava.class.path=' + classpath) # Magic line 1 driver = JPackage('sql').Our_Driver # Initiating a

问题 I'm running Java code in python using PY4J (http://py4j.sourceforge.net/). My java function returns an InputStream and I would like to manipulate it in my python code: Java code: public InputStream getPCAP(key) { InputStream inputStream = cyberStore.getPCAP(pcapStringKey); return inputStream; } Python code: from py4j.java_gateway import JavaGateway gateway = JavaGateway() input_stream = PY4J_GateWay.getPCAP(key); ... How can I get the InputStream in python? Should I convert it to something

问题 I installed Spark and I am running into problems loading the pyspark module into ipython. I'm getting the following error: ModuleNotFoundError Traceback (most recent call last) <ipython-input-2-49d7c4e178f8> in <module> ----> 1 import pyspark /opt/spark/python/pyspark/__init__.py in <module> 44 45 from pyspark.conf import SparkConf ---> 46 from pyspark.context import SparkContext 47 from pyspark.rdd import RDD 48 from pyspark.files import SparkFiles /opt/spark/python/pyspark/context.py in

问题 I am quite new to python and am trying to call python's function from java. My primary requirements are these: call should be transparent, in the sense that it should not require modifying .py file simply to enable it to be called from java. I might be given any python file with some functions inside it. I should be able to call any of these functions without requiring to modify .py file. I want to be able to send arguments of both primitive types ( int , String , floats etc.) or non

问题 I configured Eclipse in order to develop with Spark and Python. I configured : 1. PyDev with the Python interpreter 2. PyDev with the Spark Python sources 3. PyDev with the Spark Environment variables. This is my Libraries configuration : And this is my Environment configuration : I created a project named CompensationStudy and I want to run an small example and be sure that everything will go smoothly. This is my code : from pyspark import SparkConf, SparkContext import os sparkConf =

问题 I installed Zeppelin on Windows using this tutorial and this. I also installed java 8 to avoid problems. I'm now able to start the Zeppelin server, and I'm trying to run this code - %pyspark a=5*4 print("value = %i" % (a)) sc.version I'm getting this error, related to py4j . I had other problems with this library before (same as here), and to avoid them I replaced the library of py4j in the Zeppelin and Spark on my computer with the latest version- py4j 0.10.7 . This is the error I get-

问题 I installed Zeppelin on Windows using this tutorial and this. I also installed java 8 to avoid problems. I'm now able to start the Zeppelin server, and I'm trying to run this code - %pyspark a=5*4 print("value = %i" % (a)) sc.version I'm getting this error, related to py4j . I had other problems with this library before (same as here), and to avoid them I replaced the library of py4j in the Zeppelin and Spark on my computer with the latest version- py4j 0.10.7 . This is the error I get-