points

问题 I try to figure out how big the radii of the points in my plot in x and y direction are going to be, with their size being set by cex . I want to create a plotting function which needs this information. It appears to me as if cex would be this magical parameter and nobody actually knows what exactly it is going to do. I am creating a plot with the png function. I set a graph width and height. I set par(mar) and par(oma) . I plot an empty plot with an xlim and ylim being set, and add an

问题 I have a list of points and I want to keep the points of the list only if the distance between them is greater than a certain threshold. So, starting from the first point, if the the distance between the first point and the second is less than the threshold then I would remove the second point then compute the distance between the first one and the third one. If this distance is less than the threshold, compare the first and fourth point. Else move to the distance between the third and fourth

问题 I have a list of points and I want to keep the points of the list only if the distance between them is greater than a certain threshold. So, starting from the first point, if the the distance between the first point and the second is less than the threshold then I would remove the second point then compute the distance between the first one and the third one. If this distance is less than the threshold, compare the first and fourth point. Else move to the distance between the third and fourth

问题 Okay, here's some code ( pdfDocument is a com.itextpdf.text.Document ): PdfPTable table = new PdfPTable(1); PdfPCell cell = new PdfPCell(); cell.setFixedHeight(3f); for (int i = 1; i < 100; i++) { table.addCell(cell); } pdfDocument.add(table); According to my calculations (pixels = points / 0.75f) 3f points should be EXACTLY 4 pixels on a screen with 96dpi (which mine is). However, when I create a table with the code above, I get alternating heights of the cells 4 - 3 - 4 - 3 - 4 - 3 etc...

问题 Okay, here's some code ( pdfDocument is a com.itextpdf.text.Document ): PdfPTable table = new PdfPTable(1); PdfPCell cell = new PdfPCell(); cell.setFixedHeight(3f); for (int i = 1; i < 100; i++) { table.addCell(cell); } pdfDocument.add(table); According to my calculations (pixels = points / 0.75f) 3f points should be EXACTLY 4 pixels on a screen with 96dpi (which mine is). However, when I create a table with the code above, I get alternating heights of the cells 4 - 3 - 4 - 3 - 4 - 3 etc...

问题 I've been searching and trying to use a sample of the select point within a polygon example however I am not drawing a new polygon but rather one is already in the map to use as selection boundary. I have many points on the map as well but some are out of view or possibly hidden due to zoom ratio so I w/ant to ignore all those points from being selected even if they are in the selection polygon. Is this possible? // searchArea is populated by click method function searchPolygon(searchArea) {

问题 As for my knowledge, there is no built-in feature in OpenLayers to project the straight line of two points into curved line following the curvature of the Earth. This was a problem when I got a route that was going straight through Madagascar: Is there any solution on the frontend for this problem, any feature that I missed in OpenLayers, or is there any third-party solution to calculate this. I know that this kind of calculation is hard on the frontend, and it also depends on the resolution

来源： https://stackoverflow.com/questions/62576860/how-to-get-the-k-most-distant-points-given-their-coordinates

来源： https://stackoverflow.com/questions/62576860/how-to-get-the-k-most-distant-points-given-their-coordinates

来源： https://stackoverflow.com/questions/40920505/python-3-x-finding-saddle-points-in-a-matrix