pixel

I got the following data from some calculations: x, y, temp where x and y are the coordinates of a point in a 2D box of dimensions 10x10. Spacing is equal to 0.1. So there are 10000 different points and the resulting file looks like: 0.0 0.0 5.6 0.1 0.0 3.2 0.2 0.0 4.1 ... 9.9 9.9 2.1 I would like to prepare kind of a 2D plot with matplotlib, with 100x100 pixels, where each pixel gets a colour (rainbow colors going from red to violet, from the minimum to the maximum values of the third column) according to the value of the 3rd column, and data is read from this file. I wonder what is the best

I'm aware of AVFoundation and its capture support (not too familiar though). However, I don't see any readily-accessible API to get pixel-by-pixel data (RGB-per-pixel or similar). I do recall reading in the docs that this is possible, but I don't really see how. So: Can this be done? If so, how? Would I be getting raw image data, or data that's been JPEG-compressed? AV Foundation can give you back the raw bytes for an image captured by either the video or still camera. You need to set up an AVCaptureSession with an appropriate AVCaptureDevice and a corresponding AVCaptureDeviceInput and

I'm stuck trying to turn on a single pixel on a Windows Form. graphics.DrawLine(Pens.Black, 50, 50, 51, 50); // draws two pixels graphics.DrawLine(Pens.Black, 50, 50, 50, 50); // draws no pixels The API really should have a method to set the color of one pixel, but I don't see one. I am using C#. This will set a single pixel: e.Graphics.FillRectangle(aBrush, x, y, 1, 1); The Graphics object doesn't have this, since it's an abstraction and could be used to cover a vector graphics format. In that context, setting a single pixel wouldn't make sense. The Bitmap image format does have GetPixel()

css3的 -webkit-min-device-pixel-ratio属性 解决高清的适配 bg-image($url) background-image: url($url + "@2x.png") @media (-webkit-min-device-pixel-ratio: 3),(min-device-pixel-ratio: 3) background-image: url($url + "@3x.png") 来源： https://www.cnblogs.com/webljl/p/11345473.html