php-5.3

Can I bring back old __tostring() behaviour in PHP 5.3?

纵然是瞬间 提交于 2019-12-24 01:40:23
问题 I've got to move a web site (custom-written (not by me), so just updating a CMS is not an option) to a PHP 5.3 server. The code complains:: Fatal error: Method cDate::__tostring() cannot take arguments in ...\lib.datetime.php on line 183 I've googled to find out that the problem is because "with PHP 5.3 the magic method __tostring() no more accepts any parameter", "... implements its __tostring() by accepting parameter ... which is now deprecated in favor of the new __tostring() for PHP 5.3".

Unable to find Twig template using render method in Symfony 2

好久不见. 提交于 2019-12-24 00:09:31
问题 I am experiencing an issue trying to reference a particular Twig template. I am using the render method that is part of the SF2 main controller, but I clearly not referencing/using it correctly. This is my directory/file structure: /src /AyrshireMinis /CommonBundle /Controller DefaultController.php /Entity Link.php /Resources /views /Default links.html.twig and this is the method called by the router in DefaultContoller.php : /** * @Route("/links", name="ayrshireminis_links") * @Template() */

How to disable slash command syntax in Doxygen

馋奶兔 提交于 2019-12-23 09:27:08
问题 I've run into a problem with PHP 5.3 namespacing and Doxygen comments. Example: /** * Sample Method * * @param string $output * @return \Project\Lib\Rest */ Doxygen gives me the following warnings: warning: Found unknown command `\Project' warning: Found unknown command `\Lib' warning: Found unknown command `\Rest' What can I do to fix this or turn off \commands and only use @commands 回答1: Try escaping your backslashes, i.e. use /** * Sample Method * * @param string $output * @return \

Tumblr API V2 Error code 429: “Rate Limit Exceeded” You are being rate limited, slow down. Header info?

狂风中的少年 提交于 2019-12-22 11:37:22
问题 I tested Tumblr API with PHP, then I try to follow with friends using API and worked successfully, then later I get this error: Error 429 "Rate Limit Exceeded" I heard I need to wait 1 hour and limits will gone. Also I see a few information about headers: x_ratelimit_api_followers_limit x_ratelimit_api_followers_remaining x_ratelimit_api_followers_reset This informations can be in header. What header? Oauth? I don't found that. How can I see this variables? How can I get more information

unexpected cast to boolean?

[亡魂溺海] 提交于 2019-12-22 09:00:00
问题 Given this input: http://example.com/item.php?room=248&supply_id=18823, the following 2 blocks ought to produce the same result. Why don't they? What am I missing other than coffee? This block gives the expected values: if (isset($_GET['supply_id']) && isset($_GET['room'])) { $id=validkey($_GET['supply_id']); //18823 $room=validkey($_GET['room']); //248 $arr=array('s'=>$id,'r'=>$room); //s=>18823, r=>248 } But if I do the check and the assignment in one step, $id ends up equal to 1 instead of

How to access the property/ value of an array which has been converted into an object?

我是研究僧i 提交于 2019-12-22 07:40:44
问题 How can I access the property/ value of an array which has been converted into an object? For instance, I want to access the value in the index 0, $obj = (object) array('qualitypoint', 'technologies', 'India'); var_dump($obj->0); error, Parse error: syntax error, unexpected T_LNUMBER, expecting T_STRING or T_VARIABLE or '{' or '$' in C:...converting_to_object.php on line 11 回答1: The reason you can not access values via $obj->0 its because it against PHP variable naming see http://php.net

Converting json to array with recursive method?

这一生的挚爱 提交于 2019-12-20 05:17:27
问题 I am trying to convert json string inside an array into array, $config = array( "type" => '{"category":"admin","page":"page"}', "say" => "Hello", "php" => array( "say" => "no", "type" => '{"category":"admin","page":"page"}', "gran" =>array( "name" => "Hi" ) ) ); My working code, class objectify { public function json_to_array($array, $recursive = true) { # if $array is not an array, let's make it array with one value of former $array. if (!is_array($array)) $array = array($array); foreach(

How to generate or modify a PHP class at runtime?

徘徊边缘 提交于 2019-12-20 03:29:07
问题 The schmittjoh/cg-library seems what I need, but there is no documentation at all. This library provides some tools that you commonly need for generating PHP code. One of it's strength lies in the enhancement of existing classes with behaviors. Given A class: class A {} I'd like to modify, at runtime of course and with some cache mechanism, class A , making it implementing a given interface: interface I { public function mustImplement(); } ... with a "default" implementation for method

How to use __get() to return null in multilevel object property accessing?

萝らか妹 提交于 2019-12-20 02:28:36
问题 How can I use __get() to return null in multilevel object property accessing the case like this below? For instance, this is my classes, class property { public function __get($name) { return (isset($this->$name)) ? $this->$name : null; } } class objectify { public function array_to_object($array = array(), $property_overloading = false) { # if $array is not an array, let's make it array with one value of former $array. if (!is_array($array)) $array = array($array); # Use property overloading

In PHP, 0 (int, zero) is equal to “first” or “last” (strings)?

五迷三道 提交于 2019-12-20 02:15:49
问题 I'm confused by something I just ran into in a script I was working on. I had the following: function getPart($part) { $array = array('a', 'b', 'c'); if ($part == 'first') $part = 0; if ($part == 'last') $part = count($array) - 1; if (isset($array[$part])) return $array[$part]; return false; } $position = 0; echo getPart($position); So, if I were to try the string "first", I should get "a" as the output. With the string "last" I should get "c" and so on. When I run the script above, with PHP