partition-by

Reset Row Number on value change, but with repeat values in partition

由 和自甴很熟 提交于 2021-02-10 10:54:23
问题 I'm having trouble with something very similar to this question T-sql Reset Row number on Field Change The solution to this question is perfect, works fine. Except when I try with multiple other 'custno', it breaks down. What I mean by that: custno moddate who -------------------------------------------------- 581827 2012-11-08 08:38:00.000 EMSZC14 581827 2012-11-08 08:41:10.000 EMSZC14 581827 2012-11-08 08:53:46.000 EMSZC14 581827 2012-11-08 08:57:04.000 EMSZC14 581827 2012-11-08 08:58:35

How to Fetch records based on the Dates in MYSQL

由 爱⌒轻易说出口 提交于 2020-05-09 15:47:30
问题 I have sample data ID Name Amount cal_amt Run_amt Dates 1 Test 15000 0.00 15000 2020-06-01 1 Test 15000 0.00 30000 2020-04-01 1 Test 15000 12000 30000 2020-05-01 2 Test_1 18000 0.00 25000 2020-06-01 2 Test_1 18000 0.00 35000 2020-04-01 2 Test_1 18000 16000 35000 2020-05-01 I need to get MAX(month) of Run_Amount i.e : 2020-06-01 --> 15000 Need to fetch cal_amt of current month i.e : 2020-05-01 --> 12000 and 0.00 also relates to this month 2020-04-01 I need to get output like this : ID Name

Cannot use group by and over(partition by) in the same query?

由 血红的双手。 提交于 2020-01-10 10:05:23
问题 I have a table myTable with 3 columns. col_1 is an INTEGER and the other 2 columns are DOUBLE . For example, col_1={1, 2}, col_2={0.1, 0.2, 0.3} . Each element in col_1 is composed of all the values of col_2 and col_2 has repeated values for each element in col_1 . The 3rd column can have any value as shown below: col_1 | col_2 | Value ---------------------- 1 | 0.1 | 1.0 1 | 0.2 | 2.0 1 | 0.2 | 3.0 1 | 0.3 | 4.0 1 | 0.3 | 5.0 2 | 0.1 | 6.0 2 | 0.1 | 7.0 2 | 0.1 | 8.0 2 | 0.2 | 9.0 2 | 0.3 |

Using Row_number() OVER(partition BY..) along with declaring local variables

由 岁酱吖の 提交于 2019-12-12 06:07:23
问题 I have a sql query, in this sql query I want to select distinct columns irrespective of column first. For other sql query I use Row_number() OVER(partition BY..) and I also need to use inner join. The query in which I want to use row_number and inner join is - DECLARE @columns NVARCHAR(MAX) DECLARE @params NVARCHAR(MAX) = '@columns NVARCHAR(MAX) OUTPUT' DECLARE @sql NVARCHAR(MAX) = 'SELECT @columns = STUFF( ( SELECT '',''+ [column_name] FROM information_schema.columns WHERE (table_schema = '

Group By records based on 10 second time interval in SQL server

由 血红的双手。 提交于 2019-12-12 03:24:28
问题 Requirement is to Group record of table based on 10 second time interval. Given table Id DateTime Rank 1 2011-09-27 18:36:15 1 2 2011-09-27 18:36:15 1 3 2011-09-27 18:36:19 1 4 2011-09-27 18:36:23 1 5 2011-09-27 18:36:26 1 6 2011-09-27 18:36:30 1 7 2011-09-27 18:36:32 1 8 2011-09-27 18:36:14 2 9 2011-09-27 18:36:16 2 10 2011-09-27 18:36:35 2 Group Should be like this Id DateTime Rank GroupRank 1 2011-09-27 18:36:15 1 1 2 2011-09-27 18:36:15 1 1 3 2011-09-27 18:36:19 1 1 4 2011-09-27 18:36:23

Optimizing SUM OVER PARTITION BY for several hierarchical groups

由 旧街凉风 提交于 2019-12-07 21:12:24
问题 I have a table like below: Region Country Manufacturer Brand Period Spend R1 C1 M1 B1 2016 5 R1 C1 M1 B1 2017 10 R1 C1 M1 B1 2017 20 R1 C1 M1 B2 2016 15 R1 C1 M1 B3 2017 20 R1 C2 M1 B1 2017 5 R1 C2 M2 B4 2017 25 R1 C2 M2 B5 2017 30 R2 C3 M1 B1 2017 35 R2 C3 M2 B4 2017 40 R2 C3 M2 B5 2017 45 I need to find SUM([Spend] over different groups as follow: Total Spend over all the rows in the whole table Total Spend for each Region Total Spend for each Region and Country group Total Spend for each

Optimizing SUM OVER PARTITION BY for several hierarchical groups

由 不问归期 提交于 2019-12-06 11:38:48
I have a table like below: Region Country Manufacturer Brand Period Spend R1 C1 M1 B1 2016 5 R1 C1 M1 B1 2017 10 R1 C1 M1 B1 2017 20 R1 C1 M1 B2 2016 15 R1 C1 M1 B3 2017 20 R1 C2 M1 B1 2017 5 R1 C2 M2 B4 2017 25 R1 C2 M2 B5 2017 30 R2 C3 M1 B1 2017 35 R2 C3 M2 B4 2017 40 R2 C3 M2 B5 2017 45 I need to find SUM([Spend] over different groups as follow: Total Spend over all the rows in the whole table Total Spend for each Region Total Spend for each Region and Country group Total Spend for each Region, Country and Advertiser group So I wrote this query below: SELECT [Period] ,[Region] ,[Country] ,

Rank() over Partition by in mysql

由 自作多情 提交于 2019-11-27 09:39:23
I'm completely stumped as to create a new column "LoginRank" from rank() over(partition by x, order by y desc) in mysql. From sql server i would write the following query, to create a column "Loginrank" that is grouped by "login" and ordered by "id". select ds.id, ds.login, rank() over(partition by ds.login order by ds.id asc) as LoginRank from tablename.ds I have the following table. create table ds (id int(11), login int(11)) insert into ds (id, login) values (1,1), (2,1), (3,1), (4,2), (5,2), (6,6), (7,6), (8,1) I tried applying many existing mysql fixes to my dataset but continue to have

Rank() over Partition by in mysql

由 南笙酒味 提交于 2019-11-26 14:48:09
问题 I'm completely stumped as to create a new column "LoginRank" from rank() over(partition by x, order by y desc) in mysql. From sql server i would write the following query, to create a column "Loginrank" that is grouped by "login" and ordered by "id". select ds.id, ds.login, rank() over(partition by ds.login order by ds.id asc) as LoginRank from tablename.ds I have the following table. create table ds (id int(11), login int(11)) insert into ds (id, login) values (1,1), (2,1), (3,1), (4,2), (5
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