ordinal | 易学教程

Creating console command list - how to do it right with Java

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问题 For a homework I code in Java(with which I'm a newbie), I bump into the problem of creating a console command list. The user will be confronted with a set of commands, among which s/he will choose his/her choice with a number. Something like this: Enter your choice: 0) Create a Table 1) List All Tables 2) Delete a Table 3) Insert a Record 4) List All Records 5) Delete a Record 6) Find a Record(by =) 7) Find a Record(by >) 8) Find a Record(by <) 9) Exit The first way I have done it is as

Using the Ruby Date class for Astronomical data

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问题 ~ Approximate Solar Noon lw = 88.743 # my longitude jdate = Date.ordinal_to_jd(Time.now.year, Time.now.yday) n = (jdate - 2451545 - 0.0009 - lw / 360).round # lw is users longitude west of 0. j_noon = 2451545 + 0.0009 + lw / 360 + n puts j_noon => 2455616.24740833 As an update, part of the confusion would be that solar noon is where all calculations started since January 1, 4713 BC Greenwich noon. The correct use of Date.ordinal_to_jd has not compensated for this fact. So by adding or

SELECT in mysql using column number instead of name

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问题 Is there any way to do something like : SELECT * FROM TABLE WHERE COLUMN_NUMBER = 1; ? 回答1: If your table has a column named COLUMN_NUMBER and you want to retrieve rows from the table where that column contains a value of '1', that query should do the trick. I suspect that what you are trying to do is reference an expression in the select list with an alias. And that is not supported. An expression in the WHERE clause that references a column must reference the column by name. We can play

SELECT in mysql using column number instead of name

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Is there any way to do something like : SELECT * FROM TABLE WHERE COLUMN_NUMBER = 1; ? If your table has a column named COLUMN_NUMBER and you want to retrieve rows from the table where that column contains a value of '1', that query should do the trick. I suspect that what you are trying to do is reference an expression in the select list with an alias. And that is not supported. An expression in the WHERE clause that references a column must reference the column by name. We can play some tricks with inline views, to give an alias to an expression, but this is not efficient in terms of WHERE

Discontinuous dataset in highcharts

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问题 These are the two types of datasets I am trying to load and there are many more as per the dropdown combinations. These are 14 days datasets ( also at an hourly level for 14*24 hours) The 2 types of datasets are : 1 (continuous) 7/8/2014 0:00 9442 7/9/2014 0:00 8492 7/10/2014 0:00 9491 7/11/2014 0:00 9697 7/12/2014 0:00 7377 7/13/2014 0:00 8206 7/14/2014 0:00 9586 7/15/2014 0:00 10855 7/16/2014 0:00 9693 7/17/2014 0:00 11682 7/18/2014 0:00 9668 2 (discontinuous) 7/11/2014 0:00 1 7/16/2014 0

Discontinuous dataset in highcharts

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These are the two types of datasets I am trying to load and there are many more as per the dropdown combinations. These are 14 days datasets ( also at an hourly level for 14*24 hours) The 2 types of datasets are : 1 (continuous) 7/8/2014 0:00 9442 7/9/2014 0:00 8492 7/10/2014 0:00 9491 7/11/2014 0:00 9697 7/12/2014 0:00 7377 7/13/2014 0:00 8206 7/14/2014 0:00 9586 7/15/2014 0:00 10855 7/16/2014 0:00 9693 7/17/2014 0:00 11682 7/18/2014 0:00 9668 2 (discontinuous) 7/11/2014 0:00 1 7/16/2014 0:00 1 OR 7/9/2014 0:00 1 7/10/2014 0:00 18 7/11/2014 0:00 2 7/14/2014 0:00 2 7/15/2014 0:00 4 7/16/2014 0

Remove all characters from a string who's ordinals are out of range

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What is a good way to remove all characters that are out of the range: ordinal(128) from a string in python? I'm using hashlib.sha256 in python 2.7. I'm getting the exception: UnicodeEncodeError: 'ascii' codec can't encode character u'\u200e' in position 13: ordinal not in range(128) I assume this means that some funky character found its way into the string that I am trying to hash. Thanks! new_safe_str = some_string.encode('ascii','ignore') I think would work or you could do a list comprehension "".join([ch for ch in orig_string if ord(ch)<= 128]) [edit] however as others have said it may be

Remove all characters from a string who's ordinals are out of range

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问题 What is a good way to remove all characters that are out of the range: ordinal(128) from a string in python? I'm using hashlib.sha256 in python 2.7. I'm getting the exception: UnicodeEncodeError: 'ascii' codec can't encode character u'\u200e' in position 13: ordinal not in range(128) I assume this means that some funky character found its way into the string that I am trying to hash. Thanks! 回答1: new_safe_str = some_string.encode('ascii','ignore') I think would work or you could do a list

Do C++ enums Start at 0?

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If I have an enum that does not assign numbers to the enumerations, will it's ordinal value be 0? For example: enum enumeration { ZERO, ONE, TWO, THREE, FOUR, FIVE, SIX, SEVEN, EIGHT, NINE }; I've been able to find a post citing that the C99 standard requires a 0 ordinal number . But I know C++ ignores several things in the C99 standard. And I've also been able to find a post witnessing the compiler using an ordinal value of 1 , something I also seem recall seeing, though I can't say how long ago that was. I would really like to see an answer that confirms this for C++, but I'd also like to

How to get ordinal Weekdays in a Month

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hi i want to make a program in java where days,weekNo is parameter ..Like First Friday of the month or second Monday of the month ..and it returns the date Here's a utility method that does that, using DateUtils from Apache Commons / Lang : /** * Get the n-th x-day of the month in which the specified date lies. * @param input the specified date * @param weeks 1-based offset (e.g. 1 means 1st week) * @param targetWeekDay (the weekday we're looking for, e.g. Calendar.MONDAY * @return the target date */ public static Date getNthXdayInMonth(final Date input, final int weeks, final int