non-static

io_iterator_t enumerator; kern_return_t result; result = IOServiceAddMatchingNotification( mNotifyPort, kIOMatchedNotification, IOServiceMatching( "IOFireWireLocalNode" ), serviceMatchingCallback, (void *)0x1234, & enumerator ); serviceMatchingCallback((void *)0x1234, enumerator); if i declare serviceMatchinCallback as static then it works, but i do not want it to be static. Is there a way to pass it a non-static callback function? Thank you You could keep it static, but use the userdata to store the this pointer in addition to whatever other userdata you want (by packing them into a structure

I have recently done an update to PHP 5.4, and I get an error about static and non-static code. This is the error: PHP Strict Standards: Non-static method VTimer::get() should not be called statically in /home/jaco/public_html/include/function_smarty.php on line 371 This is the line 371: $timer = VTimer::get($options['magic']); I hope somebody can help. mamdouh alramadan That means it should be called like: $timer = (new VTimer)->get($options['magic']); The difference between static and non-static is that the first one doesn't need initialization so you can call the classname then append :: to

I have two classes Class A and ClassB: static class ClassA { static string SomeMethod() { return "I am a Static Method"; } } class ClassB { static string SomeMethod() { return "I am a Static Method"; } } I want to know what is the difference between ClassA.SomeMethod(); and ClassB.SomeMethod(); When they both can be accessed without creating an instance of the class, why do we need to create a static class instead of just using a non static class and declaring the methods as static? The only difference is that static methods in a nonstatic class cannot be extension methods . In other words,

I have a very simple class which I want to use as a subclass of another one. But when I put its code in the parent's class I get : non-static variable this cannot be referenced from a static context On the other hand when I put the sublass GenTest 's class code outside the the "parent's" class code - JavaApp1 I do not get this error. public class JavaApp1 { class GenTest { @Deprecated void oldFunction() { System.out.println("don't use that"); } void newFunction() { System.out.println("That's ok."); } } public static void main(String[] args) { GenTest x = new GenTest(); x.oldFunction(); x

I would like to print two different things depending on whether a function is called statically with Foo::print() or from an instance of Foo foo; foo.print(); EDIT: Here is a class definition that definitely does not work, as answered by a few people already. class Foo { string bla; Foo() { bla = "nonstatic"; } void print() { cout << bla << endl; } static void print() { cout << "static" << endl; } }; However, is there a good way of achieving this effect? Basically, I would like to do: if(this is a static call) do one thing else do another thing Phrased in another way, I know PHP can check if

I have two classes, one for defining the algorithm parameters and another to implement the algorithm: Class 1 (algorithm parameters): using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace VM_Placement { public static class AlgorithmParameters { public static int pop_size = 100; public static double crossover_rate = 0.7; public static double mutation_rate = 0.001; public static int chromo_length = 300; public static int gene_length = 4; public static int max_allowable_generations = 400; static Random rand = new Random(); public static double random_num