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“if” block without curly braces makes subsequent “else if” nested

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AFAIK, if an "if" block is not provided the curly braces then only 1 statement is considered inside it. e.g. if(..) statement_1; statement_2; Irrespective of tabs, only statement_1 is considered inside the if block. Following code doesn't get along with that: int main () { if(false) // outer - if if(false) // nested - if cout << "false false\n"; else if(true) cout << "true\n"; } Above code doesn't print anything. It should have printed "true" . It appears as of the else if is automatically nested inside the outer if block. g++ -Wall issues warning, but that is not the question here. Once you

PHP - Nested IF statements [closed]

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问题 I'm wondering when it's a bad idea to use multiple nested IF statements. eg: function change_password($email, $password, $new_password, $confirm_new_password) { if($email && $password && $new_password && $confirm_new_password) { if($new_password == $confirm_new_password) { if(login($email, $password)) { if(set_password($email, $new_password)) { return TRUE; } } } } } This function is used like this: if(!change_password($email, $password, $new_password, $confirm_new_password) { echo 'The form

“if” block without curly braces makes subsequent “else if” nested

阅读更多关于 “if” block without curly braces makes subsequent “else if” nested

问题 AFAIK, if an "if" block is not provided the curly braces then only 1 statement is considered inside it. e.g. if(..) statement_1; statement_2; Irrespective of tabs, only statement_1 is considered inside the if block. Following code doesn't get along with that: int main () { if(false) // outer - if if(false) // nested - if cout << "false false\n"; else if(true) cout << "true\n"; } Above code doesn't print anything. It should have printed "true" . It appears as of the else if is automatically

Is There Anything Like a Templatized Case-Statement

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问题 So I have this really ugly code: template <typename T> std::conditional_t<sizeof(T) == sizeof(char), char, conditional_t<sizeof(T) == sizeof(short), short, conditional_t<sizeof(T) == sizeof(long), long, enable_if_t<sizeof(T) == sizeof(long long), long long>>>> foo(T bar){return reinterpret_cast<decltype(foo(bar))>(bar);} I'm using nested conditional_t s to make a case-statement of sorts. Is there something out there that accomplishes this more elegantly or do I need to cook up my own