nested-if

Big-O of while loop with nested-if

由 牧云@^-^@ 提交于 2019-12-11 12:56:54
问题 I have this algorithm, and I am trying to calculate its complexity. A = {{B_1}, {B_2}, {B_3}, ..., {B_n}} t_n = 0 //for every set in A while A != empty Calculate f(t_n) for each element in A using t_n. n' = argmin(A) //n' is the element (set) in A with smallest f(t_n) t_n' = t_n' + 1 if (t_n' == Constant) B_n' = B_n' - {k} //k is an element in B_n' if(B_n' == empty) A = A - {B_n'} A is a set, and if the condition (t_n' == Constant) and if(B_n' == empty) are true , we remove an element (set)

Dot rules in nested conditional statements - COBOL

由 流过昼夜 提交于 2019-12-11 09:47:15
问题 I'm wondering if anybody can explain to me the dot ruling in nested IF statements in COBOL. Example: *The first if statement* IF SUCCESSFUL-STATUS PERFORM 8300-REPL-LNNTBI00 THRU 8300-REPL-LNNTBI00-EXIT *The second if statement* IF SUCCESSFUL-STATUS DISPLAY 'RECORD ALREADY UPDATED :' WS-INF-REC ELSE DISPLAY 'UPDATE ERROR : ' WS-INF-REC ' / ' WS-RETURN-STATUS READ INFILE INTO WS-INF-REC. Which if statement does the dot placed after "WS-INF-REC" belong to? The first IF or the second IF-ELSE? I

Nested IF statement

由 放肆的年华 提交于 2019-12-11 04:14:48
问题 The following is something I have tried after some research on nested IF's however it only gives expected results for the first part of the statement and not the remainder, can anyone explain why or do I need a different type of function? =if(h4="basic","basic",if(g17>=500,"Standard",if(h4="standard","Standard",if(g17>=750,"Standard+",if(g17<=500,"Basic",if(h4="Standard+","standard+",If(g17<=750,"Standard",if(g17>=850,"Platinum",if(h4="Platinum","Platinum",if(g17<=850,"Standard+","Platinum"))

smarty nested if condition is not working properly?

由 橙三吉。 提交于 2019-12-11 02:12:12
问题 I have written my code like this, {if $quant eq 1} {if $val neq ""} .....//some code {else} .....//some code {/if} {else if $quant eq 0} .....//some code {/if} but the above nested smarty if condition is not working as expected and it always give the results in else condition.Can anyone help me please, Don't know where am making mistake... 回答1: In smarty you have to write if else condition like that: {if $quant eq 1} {elseif $val neq ""} .....//some code {elseif $val neq "3"} .....//some code

nested “and/or” if statements

由 回眸只為那壹抹淺笑 提交于 2019-12-10 20:56:00
问题 I am working on code which creates a list and then applies both the "or" and "and" conditions to do further action: a= ["john", "carlos", "22", "70"] if (("qjohn" or "carlos") in a) and (("272" or "70") in a): print "true" else: print "not true" output: not true when I do this: a= ["john", "carlos", "22", "70"] if ("qjohn" or "cdarlos" in a) and ("272" or "d70" in a): print "true" else: print "not true" output is "true" What I am not getting is **carlos and 70** should be equal to true but it

Replacing Nested if Statement With AND

由 房东的猫 提交于 2019-12-07 06:20:16
问题 I am wondering whether nested if is better than AND statement. I have a loop that goes so many times so I am thinking of faster execution available. Below is the code that has same logic with my code. The nested if statement is inside a loop. for ( int i = 0; i < array.length; i++) { // do stuff if (x == 5) { if (y == 3) { // do stuff } } } Will my code be faster by a significant difference if I replace the nested if with this And STATEMENT? if ((x == 5) && (y == 3)) // do stuff I have read

Replacing Nested if Statement With AND

由 梦想的初衷 提交于 2019-12-05 08:24:37
I am wondering whether nested if is better than AND statement. I have a loop that goes so many times so I am thinking of faster execution available. Below is the code that has same logic with my code. The nested if statement is inside a loop. for ( int i = 0; i < array.length; i++) { // do stuff if (x == 5) { if (y == 3) { // do stuff } } } Will my code be faster by a significant difference if I replace the nested if with this And STATEMENT? if ((x == 5) && (y == 3)) // do stuff I have read this link but I didn't find the answer. I am a student and still learning, thanks for all the feedback!

AlertController is being popped every time in nested conditions swift ios

由 ╄→гoц情女王★ 提交于 2019-12-02 16:40:03
问题 I have defined an alertcontroller when username or password is not correct the alert should pop, and it is working fine. but when the username & password is matched despite matching it pops up everytime when log in. I think I have not defined nested condition in a right way? help me to sort the multiple nested condition. Code for Login import UIKit import CoreData import Foundation class ViewController: UIViewController { var usernameGlobal : String = "" @IBOutlet weak var emailText:

AlertController is being popped every time in nested conditions swift ios

由 谁都会走 提交于 2019-12-02 07:43:40
I have defined an alertcontroller when username or password is not correct the alert should pop, and it is working fine. but when the username & password is matched despite matching it pops up everytime when log in. I think I have not defined nested condition in a right way? help me to sort the multiple nested condition. Code for Login import UIKit import CoreData import Foundation class ViewController: UIViewController { var usernameGlobal : String = "" @IBOutlet weak var emailText: UITextField! @IBOutlet weak var passText: UITextField! @IBOutlet weak var loginButton: UIButton! @IBAction func

PHP - Nested IF statements [closed]

由 只谈情不闲聊 提交于 2019-11-30 09:01:36
I'm wondering when it's a bad idea to use multiple nested IF statements. eg: function change_password($email, $password, $new_password, $confirm_new_password) { if($email && $password && $new_password && $confirm_new_password) { if($new_password == $confirm_new_password) { if(login($email, $password)) { if(set_password($email, $new_password)) { return TRUE; } } } } } This function is used like this: if(!change_password($email, $password, $new_password, $confirm_new_password) { echo 'The form was not filled in correctly!'; exit; } I call all my functions like this, and I'm wondering if there's
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