natural-sort

问题 This question already has answers here : How can I sort a dictionary by key? (25 answers) Closed 5 years ago . I want to sort dictionary keys in a "natural order". If I have a dictionary with the keys d = {"key1" : object, "key11" : object, "key2" : object, "key22" : object", "jay1" : object, "jay2" : object} I want to sort this dictionary so the result is: d = { "jay1" : object, "jay2" : object, "key_1" : object, "key_2" : object, "key_11" : object, "key_22" : object"} 回答1: You can change

问题 I've seen some similar questions, but no correct answer in my case. I use the DataTables plugin to sort some tables. But we can't sort datas like numerics while they are not (nut ;-p). For example, we can't sort formatted prices like those : 2 150 000 € 4 500 000 € 225 000 € So I tried to include a DataTables plugin called "Natural sort". But it doesn't seems to work, I may do some mistakes, but I can't find them. Any help will be appreciated. All you need to see/test it : JSfiddle (try to

问题 Some long time ago I asked HERE to help with sorting the table. And user "piotrm" gave an exellent sollution, thanks to him! It works perfect! SELECT @p:=0, @parent:=0; UPDATE page p1 JOIN ( SELECT title, CASE WHEN @parent<>parent_id THEN @p:=0 ELSE @p:=@p+1 END as position, @parent:=parent_id as parent_id FROM page ORDER BY parent_id, title DESC ) p2 ON p1.title = p2.title AND p1.parent_id = p2.parent_id SET p1.position = p2.position Now I need this code to be upgraded with NATURAL SORTING.

问题 I have this table with a character varying column in Postgres 9.6: id | column ------------ 1 |IR ABC-1 2 |IR ABC-2 3 |IR ABC-10 I see some solutions typecasting the column as bytea . select * from table order by column::bytea. But it always results to: id | column ------------ 1 |IR ABC-1 2 |IR ABC-10 3 |IR ABC-2 I don't know why '10' always comes before '2'. How do I sort this table, assuming the basis for ordering is the last whole number of the string, regardless of what the character

问题 How I can sort array data alphanumerically in ruby? Suppose my array is a = [test_0_1, test_0_2, test_0_3, test_0_4, test_0_5, test_0_6, test_0_7, test_0_8, test_0_9, test_1_0, test_1_1, test_1_2, test_1_3, test_1_4, test_1_5, test_1_6, test_1_7, test_1_8, test_1_9, test_1_10, test_1_11, test_1_12, test_1_13, test_1_14, ...........test_1_121...............] I want my output to be: . . . test_1_121 . . . test_1_14 test_1_13 test_1_12 test_1_11 test_1_10 test_1_9 test_1_8 test_1_7 test_1_6 test

问题 I have table like server(id,name,ip) . When I'm trying to sort results by name, I get: srv1,srv10,srv11,srv2,srv6 but I need the results like srv1,srv2,srv6,srv10,srv11 One idea I know is ORDER BY LENGTH(name), name but I have different lengths in name column What do I need to do? 回答1: You could try this: SELECT id,name,ip,CONVERT(SUBSTRING(name FROM 4),UNSIGNED INTEGER) num ORDER BY num; 回答2: Natural sorting is not implemented in MySQL. You should try a different approach. In this example I

问题 In Ruby on Rails, the default sort order will be Vitamin A Vitamin B12 Vitamin B6 Is there a mechanism or quick way so that it will sort by a natural language way so that B6 shows before B12 ? 回答1: Try something like: class Array def smart_sort sort_by{|s| (' '+s).scan(/(\d+)|(\D+)/).map{|d, s| s || d.to_i}} end end a = ['Vitamin A', 'Vitamin B12', 'Vitamin B6'] p a.smart_sort # => ["Vitamin A", "Vitamin B6", "Vitamin B12"] It sorts alternatively by digits and by non-digits. b = ['3c17d',

问题 I have a method returning a list of String that need to be sorted. However, I'm running into the old String number sorting issue and was wondering if any one could assist with a Comparator implementation or point me in the direction of one. The list is going to return something list this: State Lower Legislative District 1 State Lower Legislative District 11 State Lower Legislative District 12 ... State Lower Legislative District 2 ... State Lower Legislative District 100 ... State Upper

问题 This question already has answers here : Natural Sort Order in C# (17 answers) Closed 2 years ago . I have been hunting around for a solution to this for a while now. When I sort the below using a string sort I have a list of: 10 10b 1111 1164 1174 23 23A 23B 23D 23E I really want the list to be: 10 10b 23 23A 23B 23D 23E 1111 1164 1174 A numerical sort does not do the job either. 回答1: If you have LINQ, you can use OrderBy : Regex digitPart = new Regex(@"^\d+", RegexOptions.Compiled); ...

问题 I have this array : var columnArray = ['columnNumber1','columnNumber6','coulmnNumber7','columnNumber11','columnNumber12']; If I do columnArray.sort(); , it gives me : columnArray: ['columnNumber1','columnNumber11','coulmnNumber12','columnNumber6','columnNumber7'] How can I sort it correctly? 回答1: Try like this: arr = arr.sort(function(a, b) { return +/\d+/.exec(a)[0] - +/\d+/.exec(b)[0]; }); Edit: Fixed it works now, it had a couple errors: http://jsbin.com/iwejik/1/edit 回答2: columnArray.sort