问题
I have been hunting around for a solution to this for a while now.
When I sort the below using a string sort I have a list of:
10
10b
1111
1164
1174
23
23A
23B
23D
23E
I really want the list to be:
10
10b
23
23A
23B
23D
23E
1111
1164
1174
A numerical sort does not do the job either.
回答1:
If you have LINQ, you can use OrderBy:
Regex digitPart = new Regex(@"^\d+", RegexOptions.Compiled);
...
myList.OrderBy(x => int.Parse(digitPart.Match(x).Value))
回答2:
The easiest is to wrap the Win32 API call as explained in https://stackoverflow.com/a/248613/631687
回答3:
using System;
using System.Collections.Generic;
using System.Text.RegularExpressions;
public class NumStrCmp : IComparer<string> {
public int Compare(string x, string y){
Regex regex = new Regex(@"(?<NumPart>\d+)(?<StrPart>\D*)",RegexOptions.Compiled);
var mx = regex.Match(x);
var my = regex.Match(y);
var ret = int.Parse(mx.Groups["NumPart"].Value).CompareTo(int.Parse(my.Groups["NumPart"].Value));
if(ret != 0) return ret;
return mx.Groups["StrPart"].Value.CompareTo(my.Groups["StrPart"].Value);
}
}
class Sample {
static public void Main(){
var data = new List<string>() {"10","10b","1111","1164","1174","23","23A","23B","23D","23E"};
data.Sort(new NumStrCmp());
foreach(var x in data){
Console.WriteLine(x);
}
}
}
来源：https://stackoverflow.com/questions/8568696/icomparer-for-natural-sorting