modulus

问题 I'm currently checking whether an entry in a loop is the 3rd iteration or not, with the following code: <?php for ($i = 0; $i < count($category_news); $i++) : ?> <div class="grid_8"> <div class="candidate snippet <?php if ($i % 3 == 2) echo "end"; ?>"> <div class="image shadow_50"> <img src="<?php echo base_url();?>media/uploads/news/<?php echo $category_news[$i]['url']; ?>" alt="Image Preview" width="70px" height="70px"/> </div> <h5><?php echo $category_news[$i]['title']?></h5> <p><?php echo

问题 I'm creating an RPN calculator for a school project. I'm having trouble with the modulus operator. Since we're using the double data type, modulus won't work on floating point numbers. For example, 0.5 % 0.3 should return 0.2 but I'm getting a division by zero exception. The instruction says to use fmod(). I've looked everywhere for fmod(), including javadocs but I can't find it. I'm starting to think it's a method I'm going to have to create? edit: hmm, strange. I just plugged in those

问题 Let's say that I need to format the output of an array to display a fixed number of elements per line. How do I go about doing that using modulus operation? Using C++, the code below works for displaying 6 elements per line but I have no idea how and why it works? for ( count = 0 ; count < size ; count++) { cout << somearray[count]; if( count % 6 == 5) cout << endl; } What if I want to display 5 elements per line? How do i find the exact expression needed? 回答1: in C++ expression a % b returns

问题 I need to test whether each number from 1 to 1000 is a multiple of 3 or a multiple of 5. The way I thought I'd do this would be to divide the number by 3, and if the result is an integer then it would be a multiple of 3. Same with 5. How do I test whether the number is an integer? here is my current code: n = 0 s = 0 while (n < 1001): x = n/3 if isinstance(x, (int, long)): print 'Multiple of 3!' s = s + n if False: y = n/5 if isinstance(y, (int, long)): s = s + n print 'Number: ' print n

问题 I'm about to start optimizations on an enormous piece of code and I need to know exactly which operations are performed when the modulus operator is used. I have been searching for quite a while, but I can't find anything about the machine code behind it. Any ideas? 回答1: If you need to know exactly which operations are performed when the modulus operator is used then I would suggest you are "doing it wrong". Modulus may be different depending on OS and underlying architecture. It may vary or

问题 I have a simple for loop: for index, (key, value) in enumerate(self.addArgs["khzObj"].nodes.items()): and I want to start a new wx horizontal boxsizer after every 3rd item to create a panel with 3 nodes each and going on for as many as are in nodes. The obvious solution is to do: if index % 3 == 0: add a horizontal spacer but the enumerate starts at 0, so 0 % 3 == 0 and it would start a new row right off the bat. I've tried doing: if index == 0: index = index + 1 but of course that doesn't

问题 $5.6/4 in C++03 states- "If both operands are nonnegative then the remainder is nonnegative;if not, the sign of the remainder is implementation-defined 74) . where Note 74 is According to work underway toward the revision of ISO C, the preferred algorithm for integer division follows the rules defined inthe ISO Fortran standard, ISO/IEC 1539:1991, in which the quotient is always rounded toward zero. C++0x states - $5.6/4- "For integral operands the / operator yields the algebraic quotient

问题 I'm going to boil this problem down to the simplest form: Let's iterate from [0 .. 5.0] with a step of 0.05 and print out 'X' for every 0.25 multiplier. for(double d=0.0; d<=5.0; d+=0.05) { if(fmod(d,0.25) is equal 0) print 'X'; } This will of course not work since d will be [0, 0.05000000001, 0.100000000002, ...] causing fmod() to fail. Extreme example is when d=1.999999999998 and fmod(d,0.25) = 1 . How to tackle this? Here is an editable online example. 回答1: I'd solve this by simply not

问题 I want to get the value of an unknown number in equation containing modulus % in Java For example: x % 26 = y if I have the value of y how can I get x 回答1: The problem is that there are either zero solutions (if Math.abs(y) >= 26 ) or an infinite 1 number of values of x that satisfy that equation for a given y . The general answer is: x = 26 * k + y for any integer value of k . You can pick whatever k you want. 2 1 In practice, the range will be limited by the range of integer values you are

问题 I came across this problem on Leetcode I saw the solution but I am unable to understand why it works. What property of modulus does it apply? How can we say that we have found a subarray with sum equal to k just by looking at the previous occurence of the modulo result? Question: Given a list of non-negative numbers and a target integer k, write a function to check if the array has a continuous subarray of size at least 2 that sums up to the multiple of k, that is, sums up to n*k where n is