module

问题 I am using apollo graphql, and it has a module with a function inside of it. export function createApollo(httpLink: HttpLink, connectToDevTools: true){ Inside this function you define the url for the graphql endpoint const uri = http://127.0.0.1/graphql for instance. I would like to import this url form a service (so that I only have to change the backend server url in one place), but I can not inject the service, for the property stays undefined. export function createApollo(httpLink:

问题 When I use IDLE the code "import statistics" runs, however when I use sublimetext while other packages, such as matplotlib, can be imported I cannot import the statistics module. It gives me this error code: import math import matplotlib import statistics I expect nothing to happen on the screen, but in the command line it spits out. Note that the first two lines of code did work. ImportError: No module named statistics [Finished in 1.2s with exit code 1] [shell_cmd: python -u "/Users/Ivan

问题 In the below example, the module outer has a private type Private and a private inner module inner . inner is able to access Private (because child modules can access their parent's private items , even if they are not parked as public). inner defines a function not_really_public_interface() . While it is marked as public, it is really only available to outer because inner itself is not public. outer.rs struct Private; mod inner { use super::Private; pub fn not_really_public_interface() ->

问题 In the below example, the module outer has a private type Private and a private inner module inner . inner is able to access Private (because child modules can access their parent's private items , even if they are not parked as public). inner defines a function not_really_public_interface() . While it is marked as public, it is really only available to outer because inner itself is not public. outer.rs struct Private; mod inner { use super::Private; pub fn not_really_public_interface() ->

问题 This question already has answers here : How can I require an optional Perl module if installed? (8 answers) Closed 2 months ago . If I want to write code that optionally uses a module how can I do it? For example, if I want to write code that warn s Dumping an object if Data::Dumper is available or otherwise just warn s, how can I do that? 回答1: BEGIN { if (eval { require Data::Dumper }) { *dumper = sub { warn(Data::Dumper::Dumper(@_)) }; } else { *dumper = sub { }; } } dumper(...); The

问题 I try to install the module contextily to use it on Python. I went on Anaconda Prompt as admin, and wrote : pip install contextily I get this error and I have still not found what I have to do : Getting requirements to build wheel ... error ERROR: Command errored out with exit status 1: command:'C:\Users\elise\AppData\Local\Continuum\anaconda3\python.exe' 'C:\Users\elise\AppData\Local\Continuum\anaconda3\lib\site-packages\pip_vendor\pep517_in_process.py' get_requires_for_build_wheel 'C:\Users

问题 Let's assume I have a main script, main.py, that imports another python file with import coolfunctions and another: import chores Now, suppose coolfunctions also uses stuff from chores, hence I declare import chores inside coolfunctions. Since both main.py, and coolfunctions import chores ~ is this redundant? Is there any other way of doing this? Am I doing it correctly? I'm confused about how python projects should be structured in general. I have a "conf.py" file, that I import for a bunch

问题 Let's say I have a module in TypeScript: export default function myModule(name: string): void { alert(`Hello, ${name}!`) } When I run tsc to build the above code, and try to import the generated code through Node.js (pure JavaScript): const myModule = require('./dist/myModule.js') myModule('Luiz') // ERROR! `myModule` is `undefined` The only way to make it work is by using .default after the require() , which is not what I want: // ↓↓↓↓↓↓↓↓ const myModule = require('./dist/myModule.js')

问题 Let's assume I have a main script, main.py, that imports another python file with import coolfunctions and another: import chores Now, suppose coolfunctions also uses stuff from chores, hence I declare import chores inside coolfunctions. Since both main.py, and coolfunctions import chores ~ is this redundant? Is there any other way of doing this? Am I doing it correctly? I'm confused about how python projects should be structured in general. I have a "conf.py" file, that I import for a bunch

问题 Error : Import-Module : The specified module 'msonline' was not loaded because no valid module file was found in any module directory The error pops up when I try to load the module by typing : Import-Module MSOnline tried to install the Azure AD powershell module on my computer so I'd be able to make PSSession using the MSONLINE cmdlets. After I installed the Microsoft Online Services Sign-in Assistant (version7.250.4556.0) and then installed the latest Windows Azure AD Module for Windows