median

If you have an AVL tree, what's the best way to get the median from it? The median would be defined as the element with index ceil(n/2) (index starts with 1) in the sorted list. So if the list was 1 3 5 7 8 the median is 5. If the list was 1 3 5 7 8 10 the median is 5. If you can augment the tree, I think it's best to let each node know the size (number of nodes) of the subtree, (i.e. 1 + left.size + right.size). Using this, the best way I can think of makes median searching O(lg n) time because you can traverse by comparing indexes. Is there a better way? Augmenting the AVL tree to store

How can I calculate the median value of a list in tensorflow? Like node = tf.median(X) X is the placeholder In numpy, I can directly use np.median to get the median value. How can I use the numpy operation in tensorflow? edit: This answer is outdated, use Lucas Venezian Povoa's solution instead. It is simpler and faster. You can calculate the median inside tensorflow using: def get_median(v): v = tf.reshape(v, [-1]) mid = v.get_shape()[0]//2 + 1 return tf.nn.top_k(v, mid).values[-1] If X is already a vector you can skip the reshaping. If you care about the median value being the mean of the

I have a script which counts median value for all table data: SELECT avg(t1.price) as median_val FROM ( SELECT @rownum:=@rownum+1 as `row_number`, d.price FROM mediana d, (SELECT @rownum:=0) r WHERE 1 ORDER BY d.price ) as t1, ( SELECT count(*) as total_rows FROM mediana d WHERE 1 ) as t2 AND t1.row_number>=total_rows/2 and t1.row_number<=total_rows/2+1; Now I need to get median value not for all table values, but grouped by date. Is it possible? http://sqlfiddle.com/#!2/7cf27 - so as result I will get 2013-03-06 - 1.5 , 2013-03-05 - 3.5. I hope I didn't loose myself and overcomplicate things,

I need to calculate median value of a numeric sequence in Google BigQuery efficiently. Is the same possible? Yeah it's possible with PERCENTILE_CONT window function. Returns values that are based upon linear interpolation between the values of the group, after ordering them per the ORDER BY clause. must be between 0 and 1. This window function requires ORDER BY in the OVER clause. So an example query would be like (the max() is there just to work across the group by but it's not being used as a math logic, should not confuse you) SELECT room, max(median) FROM (SELECT room, percentile_cont(0.5)

Problem The median of M numbers is defined as the 1) if M is odd middle number after sorting them in order 2) if M is even the average number of the middle 2 numbers (again after sorting) You have an empty number list at first. Then you can add or remove some number from the list. For each add or remove operation, output the median of numbers in the list. Example : For a set of m = 5 numbers, { 9, 2, 8, 4, 1 } the median is the third number in sorted set { 1, 2, 4, 8, 9 } which is 4. Similarly for set of m = 4, { 5, 2, 10, 4 }, the median is the average of second and the third element in the

I want to compute the Median of y in sub groups of this simple xy_table : x | y --groups--> gid | x | y --medians--> gid | x | y ------- ------------- ------------- 0.1 | 4 0.0 | 0.1 | 4 0.0 | 0.1 | 4 0.2 | 3 0.0 | 0.2 | 3 | | 0.7 | 5 1.0 | 0.7 | 5 1.0 | 0.7 | 5 1.5 | 1 2.0 | 1.5 | 1 | | 1.9 | 6 2.0 | 1.9 | 6 | | 2.1 | 5 2.0 | 2.1 | 5 2.0 | 2.1 | 5 2.7 | 1 3.0 | 2.7 | 1 3.0 | 2.7 | 1 In this example every x is unique and the table is already sorted by x . I now want to GROUP BY round(x) and get the tuple that holds the median of y in each group. I can already compute the median for the whole

I've been trying to calculate median but still I've got some mathematical issues I guess as I couldn't get the correct median value and couldn't figure out why. Here's the code; class StatsCollector { constructor() { this.inputNumber = 0; this.average = 0; this.timeout = 19000; this.frequencies = new Map(); for (let i of Array(this.timeout).keys()) { this.frequencies.set(i, 0); } } pushValue(responseTimeMs) { let req = responseTimeMs; if (req > this.timeout) { req = this.timeout; } this.average = (this.average * this.inputNumber + req) / (this.inputNumber + 1); console.log(responseTimeMs /