math

问题 This question already has answers here : Is & faster than % when checking for odd numbers? (8 answers) Closed 2 years ago . which is faster to find the even number if(n%2==0) or if(n&1==0) ? def isEven(n): if n%2 == 0: return True return False OR def isEven(n): if n&1 == 1: return False return True 回答1: This looks like Python, so I tried it in Python(3.6): from timeit import timeit a = timeit(stmt='for i in range(100): i%2') b = timeit(stmt='for i in range(100): i&1') print(a, b) Times vary

问题 This question already has answers here : Is & faster than % when checking for odd numbers? (8 answers) Closed 2 years ago . which is faster to find the even number if(n%2==0) or if(n&1==0) ? def isEven(n): if n%2 == 0: return True return False OR def isEven(n): if n&1 == 1: return False return True 回答1: This looks like Python, so I tried it in Python(3.6): from timeit import timeit a = timeit(stmt='for i in range(100): i%2') b = timeit(stmt='for i in range(100): i&1') print(a, b) Times vary

问题 This question already has answers here : Is & faster than % when checking for odd numbers? (8 answers) Closed 2 years ago . which is faster to find the even number if(n%2==0) or if(n&1==0) ? def isEven(n): if n%2 == 0: return True return False OR def isEven(n): if n&1 == 1: return False return True 回答1: This looks like Python, so I tried it in Python(3.6): from timeit import timeit a = timeit(stmt='for i in range(100): i%2') b = timeit(stmt='for i in range(100): i&1') print(a, b) Times vary

问题 I am django newbie and working on a math based project. I need to save texts involving mathematical symbols like integral , sigma , product etc. At the same time, I also need to emphasize or bold some texts (and do all kinds of rich text editing) and include figures that explains a mathematical concept. At present, I am just saving all the fields in a CharField (with dummy texts and without including any mathematical symbol) and have no idea how to include such a field. If you have any idea

问题 I am using data from this site to get random numbers. They come in as a buffer, which I convert to binary, then into integer. I would like to finally convert those random numbers into decimal values between 0 and 1 like Math.random() produces. For example, if I have the integer 151 , what do I need to do to make it look more like this float 0.0151234252525372 . Here is my code: const bent = require('bent') const getBuffer = bent('buffer') let array = [] async function random(){ try{ let

问题 I need to find a way to mesh triangles then to refine using refine. My vertices of my original triangles are stored inside a matrix of size nb_points * 2. My faces are stored in a nb_faces * 3 matrix. The data for each face is stored in a nb_face * 1 matrix. The meshing is done by diving the area using the middles of the segments of the triangles. Example : Origin : vertices = [0 1 ; 2 3 ; 4 1 ; 4 5]; faces = [1 2 3; 2 3 4]; data = [1 2]; Result expected after meshing : vertices = [0 1; 2 3;

问题 I'm trying to make a python proram to find derivatives and integrals as well as showing how. I have so far found that there is an integral_steps function which returns the steps used, but I have not found an equivalent for differentiation. Does anyone know if there is an equivalent? If there isn't, do you have any ideas on how to find the steps needed to find a derivative? 回答1: Method 1 (manual) Looking at the code, the Derivative class is where the top-level logic lives. That's only the top

问题 I'm trying to make a python proram to find derivatives and integrals as well as showing how. I have so far found that there is an integral_steps function which returns the steps used, but I have not found an equivalent for differentiation. Does anyone know if there is an equivalent? If there isn't, do you have any ideas on how to find the steps needed to find a derivative? 回答1: Method 1 (manual) Looking at the code, the Derivative class is where the top-level logic lives. That's only the top

问题 I have a project (for school) and I absolutely cant use any external libraries hence cannot use any big numbers library and I need to get the product of 2 (very) large numbers. So I thought I'll actually write my own code for it but I cant seem to get pass single digit multiplications. How I've done it so far is I have an array of chars 'a'. And Ill multiply each of its digits with the other number (since no multiplication can go beyond 81 ie, 9*9). But I cant seem to figure out how Ill

问题 I can't begin to understand how to approach this problem. Can someone help me to just point me in the direction as to how I can approach it? N tasks are given and there are M workers that are available. Each worker can takes different times to complete each task. The time taken by each worker for every task is given. At any time only one task can be worked on by only one worker. But the condition is once a worker has stopped working, he can't work on any task again. I want to find out what is