lvalue

#include<stdio.h> //line 1 #include<conio.h> //line 2 void main() //line 3 { //line 4 int a=6,g=7,b=3; //line 5 clrscr(); //line 6 printf("%d",a>?g=a:g=b); //line 7 getch(); //line 8 } Case 1: before saving the file This will give an error at line no 7 'Lvalue required'. But when I compile no error will come and after running, it produced output 3. Case 2 : after saving the file And when we save this file then we get an error "Lvalue required'. sorry for my mistake and Write question here #include<stdio.h> //line 1 #include<conio.h> //line 2 void main() //line 3 { //line 4 int a=6,g=7,b=3; /

So I'm trying to use ether_aton() which returns a struct ether_addr * . I'm trying to put this in my struct ether_header *eptr (from net/ethernet.h) which has the ether_shost member. I tried this: struct ether_header *eptr; /* net/ethernet.h */ ... (struct ether_addr*)(eptr->ether_shost) = ether_aton(SRC_ETHER_ADDR); This gives me the "Error: lvalue required as left operand of assignment" I know I'm just not casting it correctly, but can't figure out how. EDIT: Ended up getting it. Thanks for the help guys. struct ether_addr* eth_addr = ether_aton(SRC_ETHER_ADDR); int i; for(i=0; i<6; i++)

I am a beginner in programming and was trying out some combinations. #include<stdio.h> int main() { int a=5; printf("%d",&a); // STATEMENT 1 printf("\n%d",a); //STATEMENT 2 printf("\n%d",&(a++)); //STATEMENT 3 printf("\n%d",a); //STATEMENT 4 return 0; } I get a error in STATEMENT 3 saying [Error] lvalue required as unary '&' operand I expected the output of STATEMENT 1 & 3 to be same as both address are the same. Also I expected the output of STATEMENT 2 to be 5 & STATEMENT 4 to be 6. I looked up and found a similar question : Lvalue required error I understood the issue in that question.From

There is an error. Is it wrong to assign a value to a[i] in the following code? Or something is wrong with conditional operators? #include<stdio.h> #include<string.h> int main(){ char a[12]="sumit tyagi"; int i=0; while(a[i]!='\0'){ a[i]>90 ? a[i]=a[i]-32 : a[i]=a[i]+32; //error in this line i++; } printf("\n %s",a); a[i]>90 ? a[i]=a[i]-32 : a[i]=a[i]+32; is not evaluated as a[i]>90 ? (a[i]=a[i]-32) : (a[i]=a[i]+32); since = has lower precedence than ?: . In standard C you can't write it as above although some compilers allow it as an extension. You could write it as the more readable (and

I have a basic C++ class .The header looks like this: #pragma once class DataContainer { public: DataContainer(void); ~DataContainer(void); int* getAgeGroup(void); int _ageGroupArray[5]; private: int _ageIndex; }; Now inside the cpp file of the class I want to intialize the _ageGroupArray[5] with default values inside the class contructor like this: #include "DataContainer.h" DataContainer::DataContainer(void) { _ageGroupArray={20,32,56,43,72}; _ageIndex=10; } int* DataContainer::getAgeGroup(void){ return _ageGroupArray; } DataContainer::~DataContainer(void) { } Doing it I am getting

In the following example: class A { private: double content; public: A():content(0) {} A operator+(const A& other) { content += other.content; return *this; } void operator=(const A& other) { content = other.content; } }; A is a simple wrapper for a double for which the + and = operators have been overloaded. In the following use: int main(int argc, char *argv[]) { A a, b, c; (a+b) = c ; // Why is this operation legal? } Why does (a+b) = c compile? I would like to know why this statement is legal, because the result of (a+b) must be an rvalue . I am not returning a reference from operator+ .