list

Transform a List<Object> to a Map<String, Integer> such that the String is not a duplicate value using Java 8 Streams

假如想象 提交于 2021-02-16 13:08:23
问题 We have a Student class as follows: class Student { private int marks; private String studentName; public int getMarks() { return marks; } public void setMarks(int marks) { this.marks = marks; } public String getStudentName() { return studentName; } public void setStudentName(String studentName) { this.studentName = studentName; } public Student(String studentName, int marks) { this.marks = marks; this.studentName = studentName; } } We have a LIST of Students as follows : List<Student>

Transform a List<Object> to a Map<String, Integer> such that the String is not a duplicate value using Java 8 Streams

别说谁变了你拦得住时间么 提交于 2021-02-16 13:04:10
问题 We have a Student class as follows: class Student { private int marks; private String studentName; public int getMarks() { return marks; } public void setMarks(int marks) { this.marks = marks; } public String getStudentName() { return studentName; } public void setStudentName(String studentName) { this.studentName = studentName; } public Student(String studentName, int marks) { this.marks = marks; this.studentName = studentName; } } We have a LIST of Students as follows : List<Student>

Transform a List<Object> to a Map<String, Integer> such that the String is not a duplicate value using Java 8 Streams

坚强是说给别人听的谎言 提交于 2021-02-16 13:03:10
问题 We have a Student class as follows: class Student { private int marks; private String studentName; public int getMarks() { return marks; } public void setMarks(int marks) { this.marks = marks; } public String getStudentName() { return studentName; } public void setStudentName(String studentName) { this.studentName = studentName; } public Student(String studentName, int marks) { this.marks = marks; this.studentName = studentName; } } We have a LIST of Students as follows : List<Student>

Python: Remove duplicates for a specific item from list

丶灬走出姿态 提交于 2021-02-16 10:52:40
问题 I have a list of item, where I want to remove the occurrence of any duplicates for one item, but keep any duplicates for the rest. I.e. I start with the following list mylist = [4, 1, 2, 6, 1, 0, 9, 8, 0, 9] I want to remove any duplicates of 0 but keep the duplicates of 1 and 9 . My current solution is the following: mylist = [i for i in mylist if i != 0] mylist.add(0) Is there a nice way of keeping one occurrence of 0 besides the following? for i in mylist: if mylist.count(0) > 1: mylist

Convert tuple of tuples to a dictionary with key value pair

眉间皱痕 提交于 2021-02-16 08:39:11
问题 I have the following tuple of tuples: tuples=((32, 'Network architectures', 5), (33, 'Network protocols', 5)) How could I turn it into a list of dictionary like this dict=[ {"id": 32, "name": "Network architectures", "parent_id": 5}, {"id": 33, "name": "Network protocols", "parent_id": 5}] 回答1: Using a list comprehension as follows. First create a list of keys which will repeat for all the tuples. Then just use zip to create individual dictionaries. tuples=((32, 'Network architectures', 5),

Convert tuple of tuples to a dictionary with key value pair

本小妞迷上赌 提交于 2021-02-16 08:37:55
问题 I have the following tuple of tuples: tuples=((32, 'Network architectures', 5), (33, 'Network protocols', 5)) How could I turn it into a list of dictionary like this dict=[ {"id": 32, "name": "Network architectures", "parent_id": 5}, {"id": 33, "name": "Network protocols", "parent_id": 5}] 回答1: Using a list comprehension as follows. First create a list of keys which will repeat for all the tuples. Then just use zip to create individual dictionaries. tuples=((32, 'Network architectures', 5),

Does python list store the object or the reference to the object?

删除回忆录丶 提交于 2021-02-16 04:29:30
问题 Size of an integer is 24 bytes and size of a char is 38 bytes, but when i insert into a list the size of the list doesn't reflect the exact size of the object that i insert. So, now I am wandering list is holding the reference of the object and the object is storing somewhere in memory. >>> sys.getsizeof(1) 24 >>> sys.getsizeof('a') 38 >>> sys.getsizeof([]) 72 >>> sys.getsizeof([1]) 80 >>> sys.getsizeof(['a']) 80 >>> sys.getsizeof('james') 42 >>> 回答1: All values in Python are boxed, they don

Convert list of lists to delimited string

感情迁移 提交于 2021-02-16 00:34:15
问题 How do I do the following using built-in modules only? I have a list of lists like this: [['dog', 1], ['cat', 2, 'a'], ['rat', 3, 4], ['bat', 5]] And from it, I'd like to produce a string representation of a table like this where the columns are delimited by tabs and the rows by newlines. dog 1 cat 2 a rat 3 4 bat 5 i.e. 'dog\t1\ncat\t2\ta\nrat\t3\t4\nbat\t5' 回答1: Like this, perhaps: lists = [['dog', 1], ['cat', 2, 'a'], ['rat', 3, 4], ['bat', 5]] result = "\n".join("\t".join(map(str,l)) for

SQL variable to hold list of integers

无人久伴 提交于 2021-02-15 08:12:16
问题 I'm trying to debug someone else's SQL reports and have placed the underlying reports query into a query windows of SQL 2012. One of the parameters the report asks for is a list of integers. This is achieved on the report through a multi-select drop down box. The report's underlying query uses this integer list in the where clause e.g. select * from TabA where TabA.ID in (@listOfIDs) I don't want to modify the query I'm debugging but I can't figure out how to create a variable on the SQL

SQL variable to hold list of integers

一个人想着一个人 提交于 2021-02-15 08:03:25
问题 I'm trying to debug someone else's SQL reports and have placed the underlying reports query into a query windows of SQL 2012. One of the parameters the report asks for is a list of integers. This is achieved on the report through a multi-select drop down box. The report's underlying query uses this integer list in the where clause e.g. select * from TabA where TabA.ID in (@listOfIDs) I don't want to modify the query I'm debugging but I can't figure out how to create a variable on the SQL