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可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am struggling with the paginator in Cakephp 2.0. While I am trying to migrate my application to 2.0 I cant find any solution to jump directly to the last page. In 1.3 it was quiet to do that from outside like this: echo $this->Html->link(__('Flights'), array('controller' => 'flights', 'action' => 'index','page' => 'last')); but this little trick putting 'page:last' in does not work anymore in 2.0. Of course there is a Paginator function called last, but this would only help if I would be already inside the app. My Problem is to access from

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Have a look at the MWE below: df <- data.frame(date=as.Date(c("06/07/2000","15/09/2000","15/10/2000","03/01/2001","17/03/2001","23/05/2001","26/08/2001"), "%d/%m/%Y"), event=c(0,0,1,0,1,1,0)) id date event 01 2000-07-06 0 01 2000-09-15 0 01 2000-10-15 1 01 2001-01-03 0 02 2001-03-17 1 02 2001-05-23 1 02 2001-08-26 0 02 2001-08-28 0 03 2001-08-29 1 03 2001-09-05 1 03 2001-09-30 0 03 2001-10-12 1 I want, grouped per ID, the number of days since the last event. My question is similar to this one . Only, I want the result grouped per ID: id date

原题链接在这里： https://leetcode.com/problems/last-stone-weight-ii/ 题目： We have a collection of rocks, each rock has a positive integer weight. Each turn, we choose any two rocks and smash them together. Suppose the stones have weights x and y with x <= y . The result of this smash is: If x == y , both stones are totally destroyed; If x != y , the stone of weight x is totally destroyed, and the stone of weight y has new weight y-x . At the end, there is at most 1 stone left. Return the smallest possible weight of this stone (the weight is 0 if there are no stones left.) Example 1: Input: [2,7,4,1,8,1

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am trying to read the last 14 days of android sms messages however it seems to take an eternity to read out all the messages from the Cursor so i limit it to the 1st 100 which dont seem to be in chronological order. Any ideas of an efficient query of th esms data in order to pull the contact and the message only? My code: Uri uriSMSURISent = Uri.parse("content://sms/sent"); // get the sms data for sent Cursor curSent = getContentResolver().query(uriSMSURISent, null, null, null,null); int i=0; while (curSent.moveToNext() && i<100) { String

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: If I do getLastInsertId() immediately after a save() , it works, but otherwise it does not. This is demonstrated in my controller: function designpage() { //to create a form Untitled $this->Form->saveField('name','Untitled Form'); echo $this->Form->getLastInsertId(); //here it works } function insertformname() { echo $this->Form->getLastInsertId(); //this doesnt echo at all } Please suggest a way to get the functionality I want. 回答1: CakePHP has two methods for getting the last inserted id: Model::getLastInsertID() and Model::getInsertID() .

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I am trying to write a program in C language(code::blocks in windows). I have added below header files, it compiles with no error, but when it comes to run the code it throws an error undefined reference to gotoxy. Find the full code. Error comes where ever I have gotoxy statements. # include # include # include # include # include #include struct node { int data; struct node *link; }; void append(struct node **,int); void in_begin(struct node **,int); void del(struct node **,int); void in_middle(struct node **,int,int); int count(struct

原题链接在这里： https://leetcode.com/problems/last-stone-weight/ 题目： We have a collection of rocks, each rock has a positive integer weight. Each turn, we choose the two heaviest rocks and smash them together. Suppose the stones have weights x and y with x <= y . The result of this smash is: If x == y , both stones are totally destroyed; If x != y , the stone of weight x is totally destroyed, and the stone of weight y has new weight y-x . At the end, there is at most 1 stone left. Return the weight of this stone (or 0 if there are no stones left.) Example 1: Input: [2,7,4,1,8,1] Output: 1 Explanation

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm storing a last-touched time in a User table in Postgres, but there are many frequent updates and enough contention that I can see examples of 3 of the same updates deadlocking. Cassandra seems a better fit for this - but should I devote a table to just this purpose? And I don't need old timestamps, just the latest. Should I use something other than Cassandra? If I should use Cassandra, any tips on table properties? The table I have in mind: CREATE TABLE ksp1.user_last_job_activities ( user_id bigint, touched_at timeuuid, PRIMARY KEY

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have two different dates and I want to know the difference in days between them. The format of the date is YYYY-MM-DD. I have a function that can ADD or SUBTRACT a given number to a date: def addonDays(a, x): ret = time.strftime("%Y-%m-%d",time.localtime(time.mktime(time.strptime(a,"%Y-%m-%d"))+x*3600*24+3600)) return ret where A is the date and x the number of days I want to add. And the result is another date. I need a function where I can give two dates and the result would be an int with date difference in days. 回答1: Use - to get the

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a highchart which shows date label on x-axis, When there are more than 10 dates I'm using a logic of dividing the total dates by 10 and giving the resulting value to step. Because of step value it is not showing the last label. Please help if anybody know's the solution. I tried with showLastLabel and endOnTick but these are not working. xAxis: { categories: xcategories, labels: { step: getStep(chartJson.length) } } function getStep(jsonLength){ var step =1; if(jsonLength>=10){ step= (parseInt)(jsonLength/10); } return step;; } 回答1: