iso8601

问题 I'm looking to output duration in iso8601 format in ruby on rails for schema.org. I already know how to output the timestamp in iso8601. e.g. video.created_at.iso8601 What I'm looking to do now is output something in the format of: <meta itemprop="duration" content="PT1M33S" /> That's the iso8601 duration format. You can read about the spec at http://en.wikipedia.org/wiki/ISO_8601#Durations Currently I'm hacking in a strftime, but that's not ideal... Time.at(@video.duration).strftime('PT%MM:

问题 ISO 8601 3.5.2 distinguishes between date-time combined values and time-only values. Time-only values model the 24-hour clock of an indeterminate day not on the calendar. For Time-Only values, 24:00 is a valid value, to distinguish the end-of-the-day from the start-of-the-day (00:00). Until explicitly attached to a day on the calendar, Time-Only values are simply a point on the segment of finite time that runs from 00:00 to 24:00. What is the current ECMA standard with respect to Time-only

问题 I have a string like this: 21.03.2016 23:59 And I need this string converted into a ISO-8601 date-time string: YYYY-MM-DDTHH:mm:ss+00:00 Is there a simple way to convert this date? I try it whit moment.js but i can't find a function to parse an existing date. 回答1: You can also do this without using moment.js. Look code as following: (new Date("03.21.2016 23:59")).toISOString() just you need to change your string 21.03.2016 23:59 (dd-mm-yyyy) to 03.21.2016 23:59 (mm-dd-yyyy) . You can easily

问题 How would you convert a timestamp to an ISO 8601 format (such as 2009-01-28T21:49:59.000Z ) in Lua? I'm specifically trying to do it by using the HttpLuaModule in Nginx. 回答1: Try os.date("!%Y-%m-%dT%TZ") or os.date("!%Y-%m-%dT%TZ",t) if t has the date in seconds since the epoch. 回答2: Or you can use: local now_date_time = os.date("!%Y%m%dT%H%M%S") --> For date_time: 20191015T042028Z local now_date = os.date("!%Y%m%d") --> For only date: 20191015 来源： https://stackoverflow.com/questions/20131891

问题 Angular requires Date objects in many places whereas JSON contains string representation of the date. I want to add an array of properties which contain date values: class Foo { public int IntProp {get;set;} public DateTime? Prop1 {get;set;} public DateTime Prop2 {get;set;} public Bar Bar {set;set;} } class Bar { public DateTime Prop {get;set;} public IEnumerable<DateTime?> Dates {get;set;} } Foo should then be serialized like this: { "IntProp": 1, "Prop1": "...", "Prop2": "...", "Bar": {

问题 I need to SELECT a ISO 8601 Date. DATE_FORMAT(date, '%Y-%m-%dT%TZ') This produces something like 2013-11-13T15:47:530Z But I need it with the offset instead of Z value: 2013-11-13T15:47:53+02:00 How can I do this with plain MySQL ? 回答1: You need to store the timezone as an extra column in DB. I do not know any DB that stores datetime with timezone/offset. Or store the date as string in ISO 8601 format with offset.. Edit: I stand somewhat corrected, with some newer databases it is possible!

问题 Does anyone have a compact / elegant map from an ISO-8601 date time string of the following form: 2013-12-28T20:30:00-0700 To a Julian day. I'm hoping to find a solution that avoids an external library and has minimal regex and string manipulation. 回答1: Here’s one way to do it. You can convert an ISO string—with a time zone offset too—to a JavaScript Date object in modern JavaScript (ES5). This works in Node.js, Chrome and Firefox. It is not yet supported in Safari or IE. If you need it to

问题 This is directly related to my question POSIX date from dates in weekly time format. However, in this question I'd like to specifically ask for how to map ISO 8601 week numbers to month of the year numbers. To me, it seems it is not possible and/or involves some non-intuitive hacks (and even these don't really work reliably) and IMO should thus be considered as something that needs to be fixed in base R . Please correct me if I'm wrong, though EDIT: seems like it the issue is closely related

问题 I am trying to convert a valid ISO 8601 string to a consistent format so that sort and search using simple lexicographical order is possible. My application could receive a date/time in any of the following formats, for example: 2015-02-05T02:05:17.000+00:00 2015-02-05T02:05:17+00:00 2015-02-05T02:05:17Z These all represent the same date/time and I would like to convert them all to a canonical form for storage, say: 2015-02-05T02:05:17.000Z My first thought was to just parse them using a

问题 I have duration value in ISO8601 format and I convert it to the value of time as an integer number of seconds as below: Duration value in ISO8601 format = "P1Y". duration = ISO8601::Duration.new(params[:duration]).to_seconds # duration would have value in float, but I need it in int, so converting it to int. time_in_seconds = (Time.now - duration).to_i I store the value in 'time_in_seconds'. So when I retrieve the value would be in int, which I want to convert back to ISO8601 duration format