intervals

问题 I've been reading other questions and had no luck. I have a table with columns (stamp,value). The 'stamp' column stores hourly timestamps. What I'm trying to do is to retrieve SUM(value) for intervals of 24 hours depending on a range of timestamps specified in the query: SELECT stamp, Sum(value) FROM table WHERE stamp >= Date_sub('2012-12-02 05:00:00', INTERVAL 1 day) AND stamp < '2013-01-01 05:00:00' GROUP BY Date(stamp) The result I'm looking for would look like this: stamp value 2012-12-02

问题 My problem: Efficient way for the program to delay in my scenario. My Scenario: I am making a quiz game for a short project, long story short. A question is answered when the user presses one of four Jbuttons having an answer on them. Then my quizengine class calls the paintbutton method showed here. After that it proceeds to call some other methods responsible for making the next question appear. Now what I want is to make the button change between two colors with decreasing time intervals.

问题 Having problems with some intervals here. The basic concpt is that i have a progress bar function, 1 per row of things, being fed info from a back end script. I ping this script every 5 seconds within an interval to an ajax call. This works, however there are problems with multiples (ie, a 2nd progress bar calls the same function) or when the item is 'closed' (a div slide) it should stop. This is some very inter-trined code, so i'll try my best to pull out the necessary parts, but note that

问题 How can I determine the largest resolution of an INTERVAL value? For example: INTERVAL '100 days and 3 seconds' => day TIME '20:05' - TIME '12:01:01' => hour AGE(NOW(), NOW() - INTERVAL '1 MONTH') => month 回答1: The question isn't 100% clear so the answer may or may not be exactly what you're looking for, but... There is a justify_interval() function, which you might want to look into. test=# select justify_interval(INTERVAL '100 days 3 seconds'); justify_interval ------------------------- 3

问题 EDIT: I found a way for the problem below, however, it works on a small dataset but still creates falses output on large datasets. Someone knows why? I can't find the mistake. Here's the code: df$continuous <- unlist(lapply(split(df, df$ID), function(x) { sapply(1:nrow(x), function(y) { any(x$start[y] - x$end[-(y:NROW(x$end))] <= 1) }) })) ORIGINAL PROBLEM: I'm working on a function to identify a gap in a series of start/end dates. The output should be FALSE if a start date begins later than

问题 I have a jQuery function that is running on setInterval(); What I want to do is stop the interval when I hover over the div being displayed, and once I hover off the div, start the interval again (aka continue cycling through the divs). any idea on how to do this in the simplest form possible? Thanks! Amit 回答1: There's Reigel's way, which works a treat, or of course just set a flag that your function checks, only doing its processing if the flag isn't set. Particularly convenient if there's

问题 I'm trying to add partitions to a table I created. I want it partitioned on "PARTITION GRP" and subpartitioned by month. But I don't know how to write the INTERVAL clause inside a subpartition. Can someone help me on this? thanks! PARTITION BY RANGE (PARTITION_GRP) SUBPARTITION BY RANGE (RPTG_MTH_DATE) INTERVAL(NUMTOYMINTERVAL(1,'MONTH')) ( PARTITION PG_0 VALUES LESS THAN (1) (SUBPARTITION PG_0_201401 VALUES LESS THAN (TO_DATE('1-FEB-2014', 'DD-MON-YYYY'))), PARTITION PG_1 VALUES LESS THAN (2

问题 I've got some sort of index, like: index <- 1:100 I've also got a list of "exclusion intervals" / ranges exclude <- data.frame(start = c(5,50, 90), end = c(10,55, 95)) start end 1 5 10 2 50 55 3 90 95 I'm looking for an efficient way (in R) to remove all the indexes that belong in the ranges in the exclude data frame so the desired output would be: 1,2,3,4, 11,12,...,48,49, 56,57,...,88,89, 96,97,98,99,100 I could do this iteratively: go over every exclusion interval (using ddply ) and

问题 I have a set of data (cost & distance) I want to aggregate those ns classes depending on the distance and find the sum of the cost for the aggregated data. Here are some example tables. Nam Cost distance 1 1005 10 2 52505 52 3 51421 21 4 651 10 5 656 0 6 5448 1 Classes Class From To 1 0 5 2 5 15 3 15 100 Result Class Sum 1 6104 2 1656 3 103926 I am doing this but it takes a lot of time to process. I sure that there is a better way to do it for (i in 1:6) { for (j in 1:3) { if((Table_numbers[i

问题 I have a time series data frame looking like this: Time Source Value 1 2016-01-20 15:10:04 C04 OPEN 2 2016-01-20 15:09:57 M04 true 3 2016-01-20 15:09:53 M02 true 4 2016-01-20 15:09:53 M03 true 5 2016-01-20 14:44:54 M04 true now I would like to group them in intervals of 5 minutes starting from 00:00:00, so that I get intervals of 0-5-10-15-20... and so on. The intervals shall be used later as a group identifier: Time Source Value Group 1 2016-01-20 15:10:04 C04 OPEN 10 2 2016-01-20 15:09:57