grep

来源： https://stackoverflow.com/questions/56673619/display-failed-pods-from-kubectl-output

来源： https://stackoverflow.com/questions/56673619/display-failed-pods-from-kubectl-output

来源： https://stackoverflow.com/questions/61456142/grep-p-supports-only-unibyte-and-utf-8-locales-in-jenkins

来源： https://stackoverflow.com/questions/63731320/grep-command-questions-grep-text-from-program-output

来源： https://stackoverflow.com/questions/4192761/grep-does-not-show-results-online-regex-tester-does

来源： https://stackoverflow.com/questions/61442341/openshift-commands-to-catch-pod-name-programmatically-scripting

问题 I am using grep to produce output that will be parsed by another program. However, that program expects output only to be numeric or zero-bytes. Now grep outputs a newline character after its output. I've checked the -Z option but it doesn't seem to work as I'm using grep for counting ( -c ). I am executing in sh , not bash . So nesting it into echo -n "$(grep -c pattern)" doesn't work either. How can I get rid off the trailing newline? 回答1: You can pipe it through tr and translate the \n to

问题 I am using grep to produce output that will be parsed by another program. However, that program expects output only to be numeric or zero-bytes. Now grep outputs a newline character after its output. I've checked the -Z option but it doesn't seem to work as I'm using grep for counting ( -c ). I am executing in sh , not bash . So nesting it into echo -n "$(grep -c pattern)" doesn't work either. How can I get rid off the trailing newline? 回答1: You can pipe it through tr and translate the \n to

问题 I am using grep to produce output that will be parsed by another program. However, that program expects output only to be numeric or zero-bytes. Now grep outputs a newline character after its output. I've checked the -Z option but it doesn't seem to work as I'm using grep for counting ( -c ). I am executing in sh , not bash . So nesting it into echo -n "$(grep -c pattern)" doesn't work either. How can I get rid off the trailing newline? 回答1: You can pipe it through tr and translate the \n to

问题 In the manual for grep , we have -o to print --only-matching patterns. Say echo foobar | grep foo would return foobar , but adding -o to grep would give only foo . Many grep options like -P , -c , etc, can be used in conjunction with git to search through all files in the Git index. However, git grep -o PAT triggers an error: unknown switch o'`. How can I print only matched string for each file in the Git index? i.e. " git grep -o PAT " My trial: for f in `git ls-files`; do grep -o PAT $f;